SSC JE Electrical 2019 with solution SET-2
If the connected light load in a house is 3000W and power sub-circuit load 6000W, then what is the total number of sub-circuits required?

3
4
6
1

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SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL ÷ Ise ÷ Ia
IL = Ise = Ia
IL ÷ Ise = Ia
IL = Ise + Ia

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