Alligation or Mixture problems Two bottles contain acid and water in the ratio 2 : 3 and 1 : 2 respectively. These are mixed in the ratio 1 : 3. What is the ratio of acid and water in the new mixture ? 11:57 23:37 7:13 1:3 11:57 23:37 7:13 1:3 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems A milk seller pays Rs. 500 per kiloliter for his milk. He adds water to it and sells the mixture at 56 P a liter, thereby making altogether 40 % profit. Find the proportion of water to milk which his customers receive? 1 : 4 2 : 3 1 : 5 4 : 1 1 : 4 2 : 3 1 : 5 4 : 1 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 27 % 26 % 29 % 21 % 27 % 26 % 29 % 21 % ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135 X = 27 So, required percentage of benzene = 27 %
Alligation or Mixture problems A man buys milk at Rs. 5 a litre and mixes it with water. By selling the mixture at Rs. 4 a litre he gains 121/2 % on his outlay. How much water did each litre of the mixture contain? None of these 32 litre 13 32 litre 45 13 litre 45 None of these 32 litre 13 32 litre 45 13 litre 45 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold? 65 l 62 l 58 l 50 l 65 l 62 l 58 l 50 l ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the tin contain 5x litres of liquids 5 x - 45 x 4 5 5 x - 45 x 1 5 + 45 = 2 5 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 1 5 + 45 = 50 litres.
Alligation or Mixture problems In a courtyard there are many chickens and goats. If heads are counted, it comes to 100 but when legs are counted, it comes to 320. Find the number of chickens and goats in the courtyard. 20 , 50 30 , 70 50 , 50 40 , 60 20 , 50 30 , 70 50 , 50 40 , 60 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Average no. of legs per head = (320 / 100) = (16 / 5) or, 3 : 2 No. of goats = (3 / 3 + 2) × 100 = 60 No. of chickens = 100 ? 60 = 40.