Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 2gh² v = 1/√(2gh) v = 2gh v = √(2gh) v = 2gh² v = 1/√(2gh) v = 2gh v = √(2gh) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two balls of masses 3 kg and 6 kg are moving with velocities of 4 m/sec and 1 m/sec respectively, towards each other along the line of their centers. After impact the 3 kg ball comes to rest. This can happen only if the coefficient of restitution between the balls is 43895 43864 43833 43835 43895 43864 43833 43835 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A funicular polygon cannot be made to pass through More than three specified points Two specified points One specified point Three specified points More than three specified points Two specified points One specified point Three specified points ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Moment of inertia of a squares of side ‘b’ about an axis through its centre of gravity, is b⁴/12 b³/4 b⁴/8 b⁴/3 b⁴/12 b³/4 b⁴/8 b⁴/3 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball is dropped from a height of 2.25 m on a smooth floor and rises to a height of 1.00 m after the bounce. The coefficient of restitution between the ball and the floor is 0.67 0.33 0.57 0.44 0.67 0.33 0.57 0.44 ANSWER DOWNLOAD EXAMIANS APP
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