Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 2gh v = 2gh² v = 1/√(2gh) v = √(2gh) v = 2gh v = 2gh² v = 1/√(2gh) v = √(2gh) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The shape of a suspended cable under its own weight, is Catenary Circular Parabolic Elliptical Catenary Circular Parabolic Elliptical ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces acting at right angles is 5 kgf and if they act at an angle of 60°, it is 37 kgf. The magnitudes of the forces are: 5 kgf, 3 kgf 2 kgf, 3 kgf 3 kgf, 4 kgf 4 kgf, 5 kgf 5 kgf, 3 kgf 2 kgf, 3 kgf 3 kgf, 4 kgf 4 kgf, 5 kgf ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One Newton force, is 10⁵ dynes 10⁴ dynes 10⁶ dynes 10³ dynes 10⁵ dynes 10⁴ dynes 10⁶ dynes 10³ dynes ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Minimum pull in a suspended cable with supports at two ends is equal to Horizontal thrust Half the weight of the cable Support reactions Resultant of horizontal thrust and support reaction Horizontal thrust Half the weight of the cable Support reactions Resultant of horizontal thrust and support reaction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A vehicle weighing w kg is to run on a circular curve of radius r. If the height of its centre of gravity above the road level is h and the distance between the centres of wheels is 2a, the maximum velocity, in order to avoid over turning, will be gra/h 4√(gra/h) ∛(gra/h) √(gra/h) gra/h 4√(gra/h) ∛(gra/h) √(gra/h) ANSWER DOWNLOAD EXAMIANS APP
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