Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 2gh² v = 2gh v = √(2gh) v = 1/√(2gh) v = 2gh² v = 2gh v = √(2gh) v = 1/√(2gh) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If A is the amplitude of particle executing simple harmonic motion, then the total energy E of the particle is Proportional to A Proportional to 1/A² Proportional to A² Independent of A Proportional to A Proportional to 1/A² Proportional to A² Independent of A ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics From a solid cylinder of height 8 cm and radius 4 cm, a right circular cone is scooped out on the same base and having the same height as that of the cylinder. The C.G. of the remainder is at a height of 5.25 cm 5.5 cm 4.5 cm 5.0 cm 5.25 cm 5.5 cm 4.5 cm 5.0 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body is dropped from a height of 100 m and at the same time another body is projected vertically upward with a velocity of 10 m/sec. The two particles will Meet after 5 sec Never meet Meet after 1 sec Meet after 10 sec Meet after 5 sec Never meet Meet after 1 sec Meet after 10 sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics M.I. of a thin ring (external diameter D, internal diameter d) about an axis perpendicular to the plane of the ring, is π/32 (D⁴ + d⁴) π/32 (D⁴ - d⁴) π/64 (D⁴ + d⁴) π/32 (D⁴ × d⁴) π/32 (D⁴ + d⁴) π/32 (D⁴ - d⁴) π/64 (D⁴ + d⁴) π/32 (D⁴ × d⁴) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A uniform rod 9 m long weighing 40 kg is pivoted at a point 2 m from one end where a weight of 120 kg is suspended. The required force acting at the end in a direction perpendicular to rod to keep it equilibrium, at an inclination 60° with horizontal, is 40 kg 100 kg 10 kg 60 kg 40 kg 100 kg 10 kg 60 kg ANSWER DOWNLOAD EXAMIANS APP
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