Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = √(2gh) v = 2gh² v = 1/√(2gh) v = 2gh v = √(2gh) v = 2gh² v = 1/√(2gh) v = 2gh ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces acting at right angles is √34 kg and acting at 60° is 70 kg. The forces are √3 kg and √5 kg 1 kg and 4 kg 2 kg and 3 kg 3 kg and 5 kg √3 kg and √5 kg 1 kg and 4 kg 2 kg and 3 kg 3 kg and 5 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A funicular polygon cannot be made to pass through More than three specified points Three specified points One specified point Two specified points More than three specified points Three specified points One specified point Two specified points ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A solid sphere of mass M and radius R rolls down a plane inclined at 0 with the horizontal. The acceleration of sphere is (where g is acceleration due to gravity) (3/7) g sin 0 (1/3) g sin0 (2/5) g sin 0 (5/7) g sin0 (3/7) g sin 0 (1/3) g sin0 (2/5) g sin 0 (5/7) g sin0 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics From the circular plate of a diameter 6 cm is cut out a circular plate whose diameter is equal to radius of the plate. The C.G. of the remainder shifts from the original position through 0.50 cm 0.75 cm 0.25 cm 1.00 cm 0.50 cm 0.75 cm 0.25 cm 1.00 cm ANSWER DOWNLOAD EXAMIANS APP
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