Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 2gh² v = 1/√(2gh) v = √(2gh) v = 2gh v = 2gh² v = 1/√(2gh) v = √(2gh) v = 2gh ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics To attain the synchronous orbit, the launch of a satellite, is done from a place On the poles On 45° latitude On 30° latitude On equator On the poles On 45° latitude On 30° latitude On equator ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The equation of motion of a particle starting from rest along a straight line is x = t3 - 3l2 + 5. The ratio of the velocities after 5 sec and 3 sec will be 4 2 3 5 4 2 3 5 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One Newton is equivalent to 9.81 kg. wt 1 kg. wt 981 dyne 1/9.81 kg. wt 9.81 kg. wt 1 kg. wt 981 dyne 1/9.81 kg. wt ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics For maximum range of a projectile, the angle of projection should be 60° 45° None of these 30° 60° 45° None of these 30° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of a trapezoidal dam section whose top width is a, bottom width is band the vertical side is a, from its vertical face is (b² + bc + c²)/3 (b + c) None of these (a² + ab + c²)/3 (a + c) (a² + ab + b²)/3 (a + b) (b² + bc + c²)/3 (b + c) None of these (a² + ab + c²)/3 (a + c) (a² + ab + b²)/3 (a + b) ANSWER DOWNLOAD EXAMIANS APP
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