Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 1/√(2gh) v = 2gh v = √(2gh) v = 2gh² v = 1/√(2gh) v = 2gh v = √(2gh) v = 2gh² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics An ordinate in a funicular polygon represents Bending moment Shear force Resultant force Equilibrium Bending moment Shear force Resultant force Equilibrium ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² - y²) y = ω √(y - r) v = ω √(y² - r²) v = ω √(r² + y²) v = ω √(r² - y²) y = ω √(y - r) v = ω √(y² - r²) v = ω √(r² + y²) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 6t - 2 3t² + 2t 6t + 2 3t³ - 2t 6t - 2 3t² + 2t 6t + 2 3t³ - 2t ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘P’ is the force acting on a body whose mass is ‘m’ and acceleration is ‘f’. The equation P - mf= 0, is known as Equation of statics None of these Equation of dynamic equilibrium Equation of dynamics Equation of statics None of these Equation of dynamic equilibrium Equation of dynamics ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A system of coplanar forces is in equilibrium when Both force polygon" and funicular polygon close Funicular polygon closes All the forces are concurrent Force polygon closes Both force polygon" and funicular polygon close Funicular polygon closes All the forces are concurrent Force polygon closes ANSWER DOWNLOAD EXAMIANS APP
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