Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 1/√(2gh) v = 2gh² v = √(2gh) v = 2gh v = 1/√(2gh) v = 2gh² v = √(2gh) v = 2gh ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics An ordinate in a funicular polygon represents Shear force Bending moment Resultant force Equilibrium Shear force Bending moment Resultant force Equilibrium ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The Centre of gravity of a 10 × 15 × 5 cm T section from its bottom, is 5.0 cm 8.75 cm 7.5 cm 7.85 cm 5.0 cm 8.75 cm 7.5 cm 7.85 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 3t³ - 2t 3t² + 2t 6t - 2 6t + 2 3t³ - 2t 3t² + 2t 6t - 2 6t + 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The piston of a steam engine moves with a simple harmonic motion. The crank rotates 120 r.p.m. and the stroke length is 2 meters. The linear velocity of the piston when it is at a distance of 0.5 metre from the centre, is 8.88 m/sec 12.88 m/sec 10.88 m/sec 5.88 m/sec 8.88 m/sec 12.88 m/sec 10.88 m/sec 5.88 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Rate of change of angular momentum is equal to Linear momentum Force Torque Impulse Linear momentum Force Torque Impulse ANSWER DOWNLOAD EXAMIANS APP
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