Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 2gh v = √(2gh) v = 2gh² v = 1/√(2gh) v = 2gh v = √(2gh) v = 2gh² v = 1/√(2gh) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Rate of change of angular momentum is equal to Impulse Torque Force Linear momentum Impulse Torque Force Linear momentum ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The rate of change of displacement of a body with respect to its surrounding, is known Velocity Acceleration None of these Speed Velocity Acceleration None of these Speed ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a body is lying on a plane whose inclination with the horizontal is less than the angle of friction, theni. a force is required to move the body upwardsii. a force is required to move the body downwardiii. the body will not be in equilibriumThe correct answer is both (i) and (iii) only (i) only (ii) both (i) and (ii) both (i) and (iii) only (i) only (ii) both (i) and (ii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the velocity of projection is 4 m/sec and the angle of projection is α°, the maximum height of the projectile from a horizontal plane, is u² sin² α/2g u² tan² α/2g u² sin 2α/2g u² cos² α/2g u² sin² α/2g u² tan² α/2g u² sin 2α/2g u² cos² α/2g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The Centre of gravity of a 10 × 15 × 5 cm T section from its bottom, is 7.85 cm 5.0 cm 7.5 cm 8.75 cm 7.85 cm 5.0 cm 7.5 cm 8.75 cm ANSWER DOWNLOAD EXAMIANS APP
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