Engineering Thermodynamics The value of the product of molecular weight and the gas characteristic constant for all the gases in M.K.S. unit is 427 kgfm/mol °K 8314 kgfm/mol °K 848 kgfm/mol °K 29.27 kgfm/mol °K 427 kgfm/mol °K 8314 kgfm/mol °K 848 kgfm/mol °K 29.27 kgfm/mol °K ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The unit of time in S.I. units is Day Minute Second Hour Day Minute Second Hour ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The unit of pressure in S.I. units is Dyne per square cm Pascal kg/cm² mm of water column Dyne per square cm Pascal kg/cm² mm of water column ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The general gas equation is (where p = Pressure, v = Volume, m = mass, T = Absolute temperature, and R = Gas constant) pv = RTm pv = (RT)m pvm = C pv = mRT pv = RTm pv = (RT)m pvm = C pv = mRT ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Work-done during adiabatic expansion is given by (where p1 v1, T1 = Pressure, volume and temperature for the initial condition of gas, p2, v2, T2 = Corresponding values for the final condition of gas, R = Gas constant, and γ = Ratio of specific heats) All of these [m R (T1 - T2)] /(γ - 1) [m R T1/(γ - 1)][1 - (p2, v2 /p1 v1)] (p1 v1 - p2, v2)/(γ - 1) All of these [m R (T1 - T2)] /(γ - 1) [m R T1/(γ - 1)][1 - (p2, v2 /p1 v1)] (p1 v1 - p2, v2)/(γ - 1) ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The door of a running refrigerator inside a room was left open. Which of the following statements is correct? The room will be gradually warmed up The temperature of the air in room will remain unaffected The room will be cooled very slightly The room will be cooled to the temperature inside the refrigerator The room will be gradually warmed up The temperature of the air in room will remain unaffected The room will be cooled very slightly The room will be cooled to the temperature inside the refrigerator ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS