Stoichiometry The value of the gas-law constant 'R' is 1.987 Kcal/kg-mole.°C Kcal/kg-mole.°K Both B & C Btu/lb-mole.°R Kcal/kg-mole.°C Kcal/kg-mole.°K Both B & C Btu/lb-mole.°R ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry No cooling occurs, when an ideal gas undergoes unrestrained expansion, because the molecules Collide without loss of energy Exert no attractive force on each other Do work equal to loss in kinetic energy Are above the inversion temperature Collide without loss of energy Exert no attractive force on each other Do work equal to loss in kinetic energy Are above the inversion temperature ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Applicability of Claussius-Clapeyron equation is subject to the condition that the Neither A nor B Both A & B Vapor follows ideal gas law Volume in the liquid state is negligible Neither A nor B Both A & B Vapor follows ideal gas law Volume in the liquid state is negligible ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Increasing the temperature of an aqueous solution will cause decrease in its Molarity Mole fraction Weight percent Molality Molarity Mole fraction Weight percent Molality ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Heat of neutralisation of a strong acid and strong base is always a constant value, i.e., 57 KJ/Kg mole. This is because Only OH⁻ and H⁺ ions react in every case The strong base and strong acid reacts in aqueous solution The salt formed does not hydrolyse The strong base and strong acid reacts completely Only OH⁻ and H⁺ ions react in every case The strong base and strong acid reacts in aqueous solution The salt formed does not hydrolyse The strong base and strong acid reacts completely ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry A solution is made by dissolving 1 kilo mole of solute in 2000 kg of solvent. The molality of the solution is 0.5 1 0.5 2 0.5 1 0.5 2 ANSWER DOWNLOAD EXAMIANS APP
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