Electric Circuits The thevnin equivalent of the circuit shown in the figure is 0.75 V, 1.5 Ohm 1.5V, 1.5 Ohm 0.75V, 5/6 Ohm 1.5V, 5/6 Ohm 0.75 V, 1.5 Ohm 1.5V, 1.5 Ohm 0.75V, 5/6 Ohm 1.5V, 5/6 Ohm ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Consider the following circuit. What is the value of i ? 6 A. 5 A. - 5 A. 12 A. 6 A. 5 A. - 5 A. 12 A. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The maximum value of a current wave is 2A. If the form factor of a current wave is 1.5 and the peak factor is 2.7, find the average value in Amperes. 1.57 A. 0.494 A. 1.414 A. 0.741 A. 1.57 A. 0.494 A. 1.414 A. 0.741 A. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Reciprocity condition for h parameters is h12 = h21. h12 = - h21. h11h22 - h21h12 = 0. h12 = h21. h12 = h21. h12 = - h21. h11h22 - h21h12 = 0. h12 = h21. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Two resistors R1 and R2 give combined resistance of 4.5 Ohm when connected in series and 1 Ohm when in parallel, the resistances are 2.2 Ohm and 2.3 Ohm. 2 Ohm and 2.5 Ohm. 1.25 Ohm and 3.25 Ohm. 1.5 Ohm and 3 Ohm. 2.2 Ohm and 2.3 Ohm. 2 Ohm and 2.5 Ohm. 1.25 Ohm and 3.25 Ohm. 1.5 Ohm and 3 Ohm. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Disadvantages of constant k type filter characteristic impedance unchanged in pass band. both A and B. attenuation does not increase rapidly beyond cut off frequency. none of these. characteristic impedance unchanged in pass band. both A and B. attenuation does not increase rapidly beyond cut off frequency. none of these. ANSWER DOWNLOAD EXAMIANS APP
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