Structural Analysis The test strength of the sample is taken as the average of the strength of 3 specimens 2 specimens 4 specimens 5 specimens 3 specimens 2 specimens 4 specimens 5 specimens ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis When a uniformly distributed load, shorter than the span of the girder, moves from left to right, then the conditions for maximum bending moment at a section is that the head of the load reaches the section the tail of the load reaches the section the load position should be such that the section divides it equally on both sides the load position should be such that the section divides the load in the same ratio as it divides the span the head of the load reaches the section the tail of the load reaches the section the load position should be such that the section divides it equally on both sides the load position should be such that the section divides the load in the same ratio as it divides the span ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis Bending moment at any section in a conjugate beam gives in the actual beam slope curvature deflection bending moment slope curvature deflection bending moment ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis Degree of kinematic indeterminacy of a pin-jointed plane frame is given by 2j – r 3j – r 2j + r j – 2r 2j – r 3j – r 2j + r j – 2r ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis For stable structures, one of the important properties of flexibility and stiffness matrices is that the elements on the main diagonal(i) Of a stiffness matrix must be positive(ii) Of a stiffness matrix must be negative(iii) Of a flexibility matrix must be positive(iv) Of a flexibility matrix must be negativeThe correct answer is (i) and (iii) (ii) and (iv) (i) and (iv) (ii) and (iii) (i) and (iii) (ii) and (iv) (i) and (iv) (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis The degree of static indeterminacy of a pin-jointed space frame is given by (where m is number of unknown member forces, r is unknown reaction components and j is number of joints) m + r + 3j m + r – 2j 3m + r – 3j m + r – 3j m + r + 3j m + r – 2j 3m + r – 3j m + r – 3j ANSWER DOWNLOAD EXAMIANS APP
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