Applied Mechanics and Graphic Statics The shape of a suspended cable for a uniformly distributed load over it is Cubic parabola Catenary Circular Parabolic Cubic parabola Catenary Circular Parabolic ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Pick up the incorrect statement from the following. In a simple harmonic motion Acceleration is zero at the mean position Velocity is minimum at the end of the stroke Acceleration is minimum at the end of the stroke Velocity is maximum at its mean position Acceleration is zero at the mean position Velocity is minimum at the end of the stroke Acceleration is minimum at the end of the stroke Velocity is maximum at its mean position ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π + 0.5) [r (π + 0.25)]/(π - 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π + 0.5) [r (π + 0.25)]/(π - 0.5) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One Newton is equivalent to 1/9.81 kg. wt 9.81 kg. wt 981 dyne 1 kg. wt 1/9.81 kg. wt 9.81 kg. wt 981 dyne 1 kg. wt ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The length of a Second's pendulum, is 99.0 cm 100 cm 101 cm 99.4 cm 99.0 cm 100 cm 101 cm 99.4 cm ANSWER DOWNLOAD EXAMIANS APP
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