Electrical Machines The rotor speed of an induction motor is given by None of these Nr = 120f / p × (1-s). Ns = 120f /p × ( 1 - r). Ns = 120f / p × ( 1 - s ). None of these Nr = 120f / p × (1-s). Ns = 120f /p × ( 1 - r). Ns = 120f / p × ( 1 - s ). ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Exciting current of an induction motor is equal as power transformer. none of these. lesser than power transformer. higher than power transformer. equal as power transformer. none of these. lesser than power transformer. higher than power transformer. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The mmf produced by rotor currents of a 3 - Φ induction motor rotates at synchronous speed with respect to rotor. is at standstill with respect to stator mmf. rotates at slip speed with respect to stator mmf. rotates at the speed of rotor in the air gap. rotates at synchronous speed with respect to rotor. is at standstill with respect to stator mmf. rotates at slip speed with respect to stator mmf. rotates at the speed of rotor in the air gap. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Cogging in induction motor occurs when number of stator teeth - number of rotor teeth = even number. number of stator teeth - number of rotor teeth = negative number. number of stator teeth - number of rotor teeth = 0. number of stator teeth - number of rotor teeth = odd number. number of stator teeth - number of rotor teeth = even number. number of stator teeth - number of rotor teeth = negative number. number of stator teeth - number of rotor teeth = 0. number of stator teeth - number of rotor teeth = odd number. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Two synchronous generators operating in parallel 200 MW and 400 MW respectively. The drooping characteristics of their governors are identical as 4% from no load to full load. Consider the governors operating at 50Hz on no load. How will the machine share, if the load is 600 MW? generator 1 gets over load generator 2 gets over load 230.7 MW and 369.23 MW respectively 200 MW and 400MW respectively generator 1 gets over load generator 2 gets over load 230.7 MW and 369.23 MW respectively 200 MW and 400MW respectively ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Maximum power developed by a synchronous motor depends on supply voltage, load angle and excitation excitation and load angle supply voltage and load angle supply voltage and excitation supply voltage, load angle and excitation excitation and load angle supply voltage and load angle supply voltage and excitation ANSWER DOWNLOAD EXAMIANS APP
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