Applied Mechanics and Graphic Statics The resultant of two forces P and Q is R. If Q is doubled, the new resultant is perpendicular to P. Then, None of these P = R Q = R P = Q None of these P = R Q = R P = Q ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Kinetic friction may be defined as Friction force acting when the body is just about to move Ratio of limiting friction and normal reaction Angle between normal reaction and resultant of normal reaction and limiting friction Friction force acting when the body is in motion Friction force acting when the body is just about to move Ratio of limiting friction and normal reaction Angle between normal reaction and resultant of normal reaction and limiting friction Friction force acting when the body is in motion ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angular speed of a car while taking a circular turn of radius 100 m at 36 km/hour, is 0.1 radian/sec 1000 radian/sec 1 radian/sec 100 radian/sec 0.1 radian/sec 1000 radian/sec 1 radian/sec 100 radian/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of Applied Mechanics and Graphic Statics mcq question image (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The numbers of funicular polygons which can be drawn to pass through two specified points in the space diagram are 1 2 Zero Infinity 1 2 Zero Infinity ANSWER DOWNLOAD EXAMIANS APP
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