Applied Mechanics and Graphic Statics The resultant of two forces P and Q is R. If Q is doubled, the new resultant is perpendicular to P. Then, None of these P = R Q = R P = Q None of these P = R Q = R P = Q ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A smooth cylinder lying on its convex surface remains Out of equilibrium In neutral equilibrium In unstable equilibrium In stable equilibrium Out of equilibrium In neutral equilibrium In unstable equilibrium In stable equilibrium ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moving with a simple harmonic motion, attains its maximum velocity when it passes The extreme point of the oscillation None of these Through a point at half amplitude Through the mean position The extreme point of the oscillation None of these Through a point at half amplitude Through the mean position ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The unit of force in C.G.S. system of units, is called Kg Dyne All of these Newton Kg Dyne All of these Newton ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ ANSWER DOWNLOAD EXAMIANS APP
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