Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design The belt slip occurs due to Any one of the above Heavy load Driving pulley too small Loose belt Any one of the above Heavy load Driving pulley too small Loose belt ANSWER DOWNLOAD EXAMIANS APP
Machine Design Multiple threads are used to secure Low efficiency High efficiency High mechanical advantage High load lifting capacity Low efficiency High efficiency High mechanical advantage High load lifting capacity ANSWER DOWNLOAD EXAMIANS APP
Machine Design Three different weights fall from a certain height under vacuum. They will take Same time to reach earth None of these Times proportional to weight to reach earth Times inversely proportional to weight to reach earth Same time to reach earth None of these Times proportional to weight to reach earth Times inversely proportional to weight to reach earth ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to Indian standards, total numbers of tolerance grades are 20 18 8 12 20 18 8 12 ANSWER DOWNLOAD EXAMIANS APP
Machine Design A key way lowers The strength of the shaft The rigidity of the shaft Both the strength and rigidity of the shaft The ductility of the shaft The strength of the shaft The rigidity of the shaft Both the strength and rigidity of the shaft The ductility of the shaft ANSWER DOWNLOAD EXAMIANS APP
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