Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design The minimum number of teeth on the pinion which will mesh with any gear without interference for 20° full depth involute teeth will be 14 24 12 18 14 24 12 18 ANSWER DOWNLOAD EXAMIANS APP
Machine Design The diameter of knuckle pin in a knuckle joint is usually taken as (where d = Diameter of the rod) 0.5 d 1.2 d d 0.8 d 0.5 d 1.2 d d 0.8 d ANSWER DOWNLOAD EXAMIANS APP
Machine Design When the screw in a mechanical screw jack rotates, the load kept on the top of it moves Axially upwards or downwards Axially upwards None of these Axially downwards Axially upwards or downwards Axially upwards None of these Axially downwards ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of driving tensions for flat belts, neglecting centrifugal tension, is (where T₁, and T₂ = Tensions on the tight and slack sides of belt respectively, μ = Coefficient of friction, between the belt and pulley, and θ = Angle of contact) T₁/T₂ = μθ log (T₁/T₂) = μθ T₁/T₂ = log μθ T₁/T₂ =eμθ T₁/T₂ = μθ log (T₁/T₂) = μθ T₁/T₂ = log μθ T₁/T₂ =eμθ ANSWER DOWNLOAD EXAMIANS APP
Machine Design When a closely coiled helical spring is subjected to a couple about its axis, the stress induced in the wire material of the spring is A combination of torsional shear stress and bending A combination of bending stress and direct shear stress Direct shear stress only Bending stress only A combination of torsional shear stress and bending A combination of bending stress and direct shear stress Direct shear stress only Bending stress only ANSWER DOWNLOAD EXAMIANS APP
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