Let the two consecutive odd numbers be 2x - 1 and 2x + 1.(2x - 1) (2x - 1) = 4095= 4x² - 1 = 4095= 4x² = 4096= x² = 1024∴ x = 32∴ The numbers are 63 and 65.Greater number = 65
Let the no. be 10x + y.No. formed by the interchange of digits = 10y + xWe have y - x = 2 .........(i)y + x = 14 .........(ii)Solving (i) and (ii), we get x = 6, and y = 8∴ the no. is 68.
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