Let the two consecutive odd numbers be 2x - 1 and 2x + 1.(2x - 1) (2x - 1) = 4095= 4x² - 1 = 4095= 4x² = 4096= x² = 1024∴ x = 32∴ The numbers are 63 and 65.Greater number = 65
Let the number of children be 'x' Therefore, each child will receiveX x 60/100 = 3x/5 chocolates∴ X x 3x/5 = 735∴ x² x 735x5/3 = 1225∴ x = 1225 = 35∴ Number of chocolates = 3x/5 = 21
Let the number be 10x + y.∴ x + y = 12 ...........(i)10x + y - (10x + x) = 18or 10x + y - 10y - x = 18or 9x - 9y = 18∴ x - y = 2From (i) and (ii), x = 7, y = 5∴ Number = 75
EXAMIANS