Electrical Machines The power factor of an induction motor operating at no load will have a value around 0.2 lead 0.9 lag 0.2 lag unity 0.2 lead 0.9 lag 0.2 lag unity ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Voltage regulation of transformer is given by (E2 - V2) / E2 (V2 - E2) / V2 (V2 - E2) / E2 (E2 - V2) / V2 (E2 - V2) / E2 (V2 - E2) / V2 (V2 - E2) / E2 (E2 - V2) / V2 ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A slip ring Induction motor runs at 290 rpm at full load, when connected to 50 Hz supply. Determine the number of poles and slip. P = 40, s = 5.79 %. P = 20, s = 3.33 %. P = 50, s = 4.43 %. P = 60, s = 0.96 %. P = 40, s = 5.79 %. P = 20, s = 3.33 %. P = 50, s = 4.43 %. P = 60, s = 0.96 %. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In case of a conductively compensated DC series motor, the compensating winding is provided In series with the armature winding. In parallel with the armature winding. In parallel with the field winding. As a separate unit. In series with the armature winding. In parallel with the armature winding. In parallel with the field winding. As a separate unit. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines For a DC Shunt Motor having armature resistance of 0.5 Ω and 2A armature current at no-load, when the armature current is changed to 20A at loaded condition the speed is 1000 r.p.m. What is the speed at no-load? 963.8 r.p.m. 4575.4 r.p.m. 1037.5 r.p.m. 1130 r.p.m. 963.8 r.p.m. 4575.4 r.p.m. 1037.5 r.p.m. 1130 r.p.m. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines For P pole machine relation between electrical degrees and mechanical degrees is θelec = 4/P*θmech θelec = 2/P*θmech θelec = P/2*θmech θelec = θmech θelec = 4/P*θmech θelec = 2/P*θmech θelec = P/2*θmech θelec = θmech ANSWER DOWNLOAD EXAMIANS APP