Structural Analysis The number of independent equations to be satisfied for static equilibrium in a space structure is 8 9 6 7 8 9 6 7 ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis Which of the following methods of structural analysis is a displacement method? Moment distribution method Column analogy method None of these Three moment equation Moment distribution method Column analogy method None of these Three moment equation ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis Study the following statements. i) The displacement method is more useful when degree of kinematic indeterminacy is greater than the degree of static indeterminacy. ii) The displacement method is more useful when degree of kinematic indeterminacy is less than the degree of static indeterminacy. iii) The force method is more useful when degree of static indeterminacy is greater than the degree of kinematic indeterminacy. iv) The force method is more useful when degree of static indeterminacy is less than the degree of kinematic indeterminacy. The correct answer is (i) and (iii) (ii) and (iv) (ii) and (iii) (i) and (iv) (i) and (iii) (ii) and (iv) (ii) and (iii) (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis The thickness of the rectangular plate for the cap or base of a solid round steel columns, is calculated from the formula t = √[(9W/16 fbct) × D/(D -d)] where ‘d’ is The dimension of the base The reduced diameter of the column The diameter of the base The diameter of the top The dimension of the base The reduced diameter of the column The diameter of the base The diameter of the top ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis A single rolling load of 8 kN rolls along a girder of 15 m span. The absolute maximum bending moment will be 60 kN.m 15 kN.m 30 kN.m 8 kN.m 60 kN.m 15 kN.m 30 kN.m 8 kN.m ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis The degree of static indeterminacy of a pin-jointed space frame is given by (where m is number of unknown member forces, r is unknown reaction components and j is number of joints) m + r + 3j m + r – 3j 3m + r – 3j m + r – 2j m + r + 3j m + r – 3j 3m + r – 3j m + r – 2j ANSWER DOWNLOAD EXAMIANS APP
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