Applied Mechanics and Graphic Statics The motion of a particle is described by the relation x = t²- 10t + 30, where x is in meters and t in seconds. The total distance travelled by the particle from t = 0 to t = 10 seconds would be 50 m 60 m Zero 30 m 50 m 60 m Zero 30 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The torque produced by a force depends on(i) The magnitude of the force(ii) The direction of the force(iii) The point of application of the force relative to origin All (i), (ii) and (iii) Both (i) and (iii) Both (i) and (ii) Only (i) All (i), (ii) and (iii) Both (i) and (iii) Both (i) and (ii) Only (i) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A point subjected to a number of forces will be in equilibrium, if Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the moments of the forces about the point is zero Two resolved parts in any two directions at right angles are equal Algebraic sum of the forces is zero Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the moments of the forces about the point is zero Two resolved parts in any two directions at right angles are equal Algebraic sum of the forces is zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A force P of 50 N and another force Q of unknown magnitude act at 90° to each other. They are balanced by a force of 130 N. The magnitude of Q is 80 N 120 N 100 N 60 N 80 N 120 N 100 N 60 N ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Time required to stop a car moving with a velocity 20 m/sec within a distance of 40 m, is 5 sec 4 sec 3 sec 2 sec 5 sec 4 sec 3 sec 2 sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π + 0.25)]/(π + 0.5) [r (π + 0.25)]/(π - 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π + 0.5) [r (π + 0.25)]/(π - 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) ANSWER DOWNLOAD EXAMIANS APP
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