Applied Mechanics and Graphic Statics The motion of a particle is described by the relation x = t²- 10t + 30, where x is in meters and t in seconds. The total distance travelled by the particle from t = 0 to t = 10 seconds would be Zero 60 m 30 m 50 m Zero 60 m 30 m 50 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The ends of a string weighing w/metre are attached to two points at the same horizontal level. If the central dip is very small, the horizontal tension of the string throughout is wl²/16d wl/4d wl²/8d wl²/4d wl²/16d wl/4d wl²/8d wl²/4d ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 3t² + 2t 3t³ - 2t 6t - 2 6t + 2 3t² + 2t 3t³ - 2t 6t - 2 6t + 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A point subjected to a number of forces will be in equilibrium, if Algebraic sum of the forces is zero Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the moments of the forces about the point is zero Two resolved parts in any two directions at right angles are equal Algebraic sum of the forces is zero Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the moments of the forces about the point is zero Two resolved parts in any two directions at right angles are equal ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone was thrown vertically upwards from the ground with a velocity of 50 m/sec. After 5 seconds another stone was thrown vertically upwards from the same place. If both the stones strike the ground at the same time, then the velocity with which the second stone was thrown should be (Assume g = 10 m/sec²) 40 m/sec 50 m/sec 15 m/sec 25 m/sec 40 m/sec 50 m/sec 15 m/sec 25 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The masses of two balls are in the ratio of 2 : 1 and their respective velocities are in the ratio of 1 : 2 but in opposite direction before impact. If the coefficient of restitution is ½, the velocities of separation of the balls will be equal to Half the original velocity in the same direction Original velocity in the opposite direction Half the original velocity in the opposite direction Original velocity in the same direction Half the original velocity in the same direction Original velocity in the opposite direction Half the original velocity in the opposite direction Original velocity in the same direction ANSWER DOWNLOAD EXAMIANS APP
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