Engineering Mechanics The moment of inertia of a square of side (a) about an axis through its center of gravity is a4/12 a4/8 a4/4 a4/36 a4/12 a4/8 a4/4 a4/36 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The energy possessed by a body, for doing work by virtue of its position, is called Potential energy Electrical energy Kinetic energy Chemical energy Potential energy Electrical energy Kinetic energy Chemical energy ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The principle of transmissibility of forces states that, when a force acts upon a body, its effect is Minimum, if it acts at the center of gravity of the body Different at different points on its line of action Maximum, if it acts at the center of gravity of the body Same at every point on its line of action Minimum, if it acts at the center of gravity of the body Different at different points on its line of action Maximum, if it acts at the center of gravity of the body Same at every point on its line of action ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Coefficient of friction depends upon Nature of surface only Area of contact only Both (A) and (B) None of these Nature of surface only Area of contact only Both (A) and (B) None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum height of a projectile on a horizontal plane, is u² sin²α/2g u² cos²α/g u² cos²α/2g u² sin²α/g u² sin²α/2g u² cos²α/g u² cos²α/2g u² sin²α/g ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
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