Engineering Mechanics The moment of inertia of a square of side (a) about an axis through its center of gravity is a4/8 a4/36 a4/12 a4/4 a4/8 a4/36 a4/12 a4/4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resultant of the two forces ‘P’ and ‘Q’ is ‘R’. If ‘Q’ is doubled, the new resultant is perpendicular to ‘P’. Then Q = R Q = 2R None of the listed here P = Q Q = R Q = 2R None of the listed here P = Q ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The ideal angle of banking provided on the curves on roads depends upon Nature of the road surface Coefficient of friction between the road and vehicle contact point (Velocity)2 of the vehicle Weight of the vehicle Nature of the road surface Coefficient of friction between the road and vehicle contact point (Velocity)2 of the vehicle Weight of the vehicle ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The time of flight (t) of a projectile on an upward inclined plane is(where u = Velocity of projection, α = Angle of projection, and β = Inclination of the plane with the horizontal.) t = g cos β/2u sin (α + β) t = 2u sin (α + β)/g cos β t = 2u sin (α - β)/g cos β t = g cos β/2u sin (α - β) t = g cos β/2u sin (α + β) t = 2u sin (α + β)/g cos β t = 2u sin (α - β)/g cos β t = g cos β/2u sin (α - β) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a thin disc of mass ‘m’ and radius ‘r’, about an axis through its center of gravity and perpendicular to the plane of the disc is mr²/8 mr²/6 mr²/2 mr²/4 mr²/8 mr²/6 mr²/2 mr²/4 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS