Engineering Mechanics The moment of inertia of a square of side (a) about an axis through its center of gravity is a4/12 a4/8 a4/36 a4/4 a4/12 a4/8 a4/36 a4/4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will None of these Slant down towards direction of pull Remain horizontal Slant up towards direction of pull None of these Slant down towards direction of pull Remain horizontal Slant up towards direction of pull ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Coplanar non-concurrent forces are those forces which __________ at one point, but their lines of action lie on the same plane. Meet Do not meet Either ‘A’ or ‘B’ None of these Meet Do not meet Either ‘A’ or ‘B’ None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio in case of an inclined plane inclined at angle 'θ' to the horizontal and weight being pulled up the inclined plane by vertical effort is cosθ cosecθ tanθ sinθ cosθ cosecθ tanθ sinθ ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics One kg force is equal to 9.8 N 7.8 N 8.9 N 12 N 9.8 N 7.8 N 8.9 N 12 N ANSWER DOWNLOAD EXAMIANS APP
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