Electric Circuits The mass of a neutron of atom is 1.675 × 10 - 27 Kg. 1.602 × 10 - 19 Kg. 1.672 × 10 - 26 Kg. 1.609 × 10 - 31 Kg. 1.675 × 10 - 27 Kg. 1.602 × 10 - 19 Kg. 1.672 × 10 - 26 Kg. 1.609 × 10 - 31 Kg. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A capacitor has a capacitance of 6 μF. Calculate the stored energy in it if a DC voltage of 100 V, is applied across it? 6 × 102 joules. 2.5 × 102 joules. 3 × 102 joules. 4 × 102 joules. 6 × 102 joules. 2.5 × 102 joules. 3 × 102 joules. 4 × 102 joules. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Disadvantages of constant k type filter attenuation does not increase rapidly beyond cut off frequency. characteristic impedance unchanged in pass band. none of these. both A and B. attenuation does not increase rapidly beyond cut off frequency. characteristic impedance unchanged in pass band. none of these. both A and B. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In the given figure the value of the source voltage is 12 V. 30 V. 44 V. 24 V. 12 V. 30 V. 44 V. 24 V. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Advantage of active filter is easy to tune. derive high impedance load. do not offer gain. both of above. easy to tune. derive high impedance load. do not offer gain. both of above. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In Cauer 1st form last element in the network is Cshunt. Lshunt. Lseries. Cseries. Cshunt. Lshunt. Lseries. Cseries. ANSWER DOWNLOAD EXAMIANS APP
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