Engineering Thermodynamics The general gas equation is (where p = Pressure, v = Volume, m = mass, T = Absolute temperature, and R = Gas constant) pv = RTm pv = mRT pvm = C pv = (RT)m pv = RTm pv = mRT pvm = C pv = (RT)m ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics When the gas is heated at constant pressure, the heat supplied Increases the temperature of the gas Increases the internal energy of the gas Both (B) and (C) Does some external work during expansion Increases the temperature of the gas Increases the internal energy of the gas Both (B) and (C) Does some external work during expansion ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics A cycle consisting of two isothermal and two isentropic processes, is known as Ericsson cycle Joule cycle Stirling cycle Carnot cycle Ericsson cycle Joule cycle Stirling cycle Carnot cycle ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The natural petroleum may be separated into Petrol Fuel oil Kerosene Lubricating oil Petrol Fuel oil Kerosene Lubricating oil ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The mass of flue gas per kg of fuel is the ratio of the Mass of oxygen in 1 kg of flue gas to the mass of oxygen in 1 kg of fuel Mass of carbon in 1 kg of fuel to the mass of carbon in 1 kg of flue gas Mass of carbon in 1 kg of flue gas to the mass of carbon in 1 kg of fuel Mass of oxygen in 1 kg of fuel to the mass of oxygen in 1 kg of flue gas Mass of oxygen in 1 kg of flue gas to the mass of oxygen in 1 kg of fuel Mass of carbon in 1 kg of fuel to the mass of carbon in 1 kg of flue gas Mass of carbon in 1 kg of flue gas to the mass of carbon in 1 kg of fuel Mass of oxygen in 1 kg of fuel to the mass of oxygen in 1 kg of flue gas ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The mass of excess air supplied is equal to (23/100) × Mass of excess carbon (23/100) × Mass of excess oxygen (100/23) × Mass of excess carbon (100/23) × Mass of excess oxygen (23/100) × Mass of excess carbon (23/100) × Mass of excess oxygen (100/23) × Mass of excess carbon (100/23) × Mass of excess oxygen ANSWER DOWNLOAD EXAMIANS APP
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