Engineering Thermodynamics The efficiency of the Carnot cycle is (where T1 and T2 = Highest and lowest temperature during the cycle) 1 - (T1/T2) 1 - (T2/T1) (T1/T2) - 1 1 + (T2/T1) 1 - (T1/T2) 1 - (T2/T1) (T1/T2) - 1 1 + (T2/T1) ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics One reversible heat engine operates between 1600 K and T2 K and another reversible heat engine operates between T2 K and 400 K. If both the engines have the same heat input and output, then temperature T2 is equal to 800 K 1000 K 1200 K 1400 K 800 K 1000 K 1200 K 1400 K ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of n = 1 in the polytropic process indicates it to be Irreversible process Isothermal process Reversible process Adiabatic process Irreversible process Isothermal process Reversible process Adiabatic process ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The ideal efficiency of a Brayton cycle with regeneration, with increase in pressure ratio will Decrease Remain unchanged Increase/decrease depending on application Increase Decrease Remain unchanged Increase/decrease depending on application Increase ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The following cycle is used for air craft refrigeration Reversed Brayton cycle Joule cycle Carnot cycle Brayton cycle Reversed Brayton cycle Joule cycle Carnot cycle Brayton cycle ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Characteristic gas constant of a gas is equal to Cp - Cv Cv /Cp Cp /Cv Cp + Cv Cp - Cv Cv /Cp Cp /Cv Cp + Cv ANSWER DOWNLOAD EXAMIANS APP
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