Engineering Thermodynamics The efficiency of the Carnot cycle is (where T1 and T2 = Highest and lowest temperature during the cycle) 1 - (T2/T1) 1 + (T2/T1) 1 - (T1/T2) (T1/T2) - 1 1 - (T2/T1) 1 + (T2/T1) 1 - (T1/T2) (T1/T2) - 1 ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Those substances which have so far not been resolved by any means into other substances of simpler form are called Molecules Atoms Compounds Elements Molecules Atoms Compounds Elements ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The heat absorbed or rejected by the working substance is given by (where ds = Increase or decrease of entropy, T = Absolute temperature, and dQ = Heat absorbed or rejected) dQ = ds/T None of the listed here δQ = T.ds δQ = T/ds dQ = ds/T None of the listed here δQ = T.ds δQ = T/ds ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The oxygen atom is ________ times heavier than the hydrogen atom. 16 8 2 32 16 8 2 32 ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics For the same compression ratio, the efficiency of Diesel cycle is __________ Otto cycle. Equal to Less than None of these Greater than Equal to Less than None of these Greater than ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The heating of a gas at constant pressure is governed by Charles' law Boyle's law Gay-Lussac law Avogadro's law Charles' law Boyle's law Gay-Lussac law Avogadro's law ANSWER DOWNLOAD EXAMIANS APP