Design of Masonry Structures The effective height of free standing non-load bearing wall and column respectively will be 1.5H and 1.5H 1.0H and 1.0H 2.0H and 1.5H 2.0H and 2.0H 1.5H and 1.5H 1.0H and 1.0H 2.0H and 1.5H 2.0H and 2.0H ANSWER DOWNLOAD EXAMIANS APP
Design of Masonry Structures Full restraint is provided by(i) Foundation footing of a wall(ii) Timber floor spanning on the wall and anchored to the wall(iii) RCC slab with a minimum bearing of 10 cm on the wall (ii) and (iii) are correct (i), (ii) and (iii) are correct (i) and (iii) are correct (i) and (ii) are correct (ii) and (iii) are correct (i), (ii) and (iii) are correct (i) and (iii) are correct (i) and (ii) are correct ANSWER DOWNLOAD EXAMIANS APP
Design of Masonry Structures In a cavity wall, both leaves of which are load bearing, the effective thickness is taken as Two-third of the sum of thickness of both the leaves Sum of thickness of both leaves Actual thickness of the stronger leaf Larger of (B) and (C) Two-third of the sum of thickness of both the leaves Sum of thickness of both leaves Actual thickness of the stronger leaf Larger of (B) and (C) ANSWER DOWNLOAD EXAMIANS APP
Design of Masonry Structures Assertion A : For eccentricity ratio exceeding 1/6, effective thickness of masonry will get reduced.Reason R : For eccentricity ratio exceeding 1/6, there will be tension on one side of the member. Select your answer according to the codes give below: A is true but R is false A is false but R is true Both A and R is true and R is the correct explanation of A Both A and R is true and R is not the correct explanation of A A is true but R is false A is false but R is true Both A and R is true and R is the correct explanation of A Both A and R is true and R is not the correct explanation of A ANSWER DOWNLOAD EXAMIANS APP
Design of Masonry Structures If ‘H’ is the height of wall between centers of supports, then the effective height of wall where concrete floors have a bearing on wall irrespective of the direction of span will be 1.0 H 0.85 H 0.75 H 1.5 H 1.0 H 0.85 H 0.75 H 1.5 H ANSWER DOWNLOAD EXAMIANS APP
Design of Masonry Structures If the horizontal cross-sectional area of a wall is 1200 cm², then the basic stress shall be multiplied by a reduction factor equal to 0.95 0.6 0.85 0.75 0.95 0.6 0.85 0.75 ANSWER DOWNLOAD EXAMIANS APP
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