Stoichiometry The crystallisation of a solute from a solution may be done by Removal of pure solvent by evaporation Changing the nature of the system by the addition of a more soluble material All of these Change of temperature thereby causing supersaturation Removal of pure solvent by evaporation Changing the nature of the system by the addition of a more soluble material All of these Change of temperature thereby causing supersaturation ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Pick out the wrong unit conversion of thermal conductivity. 1 W/cm.°C = 85.985 kcal/m.hr.°C = 57.779 BTU/ft.hr.°F 1 BTU/ft².hr.°F/ft = 1.488 kcal/m². hr.°C/m 1 BTU/ft².hr.°F/inch = 1.488 kcal/m². hr.°C/m 1 kcal/m.hr.°C = 0.672 BTU/ft.hr.°F = 1.163 W/m. °K 1 W/cm.°C = 85.985 kcal/m.hr.°C = 57.779 BTU/ft.hr.°F 1 BTU/ft².hr.°F/ft = 1.488 kcal/m². hr.°C/m 1 BTU/ft².hr.°F/inch = 1.488 kcal/m². hr.°C/m 1 kcal/m.hr.°C = 0.672 BTU/ft.hr.°F = 1.163 W/m. °K ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry If the partial pressure of the solvent in the vapor phase is equal to the vapor pressure of the solvent at that temperature, then the system is said to be at its Dew point Saturation temperature Bubble point Both B and C Dew point Saturation temperature Bubble point Both B and C ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry A butane isomerisation process produces 70 kmole/hr of pure isobutane. A purge stream removed continuously, contains 85% n-butane and 15% impurity (mole%). The feed stream is n-butane containing 1% impurity (mole%). The flow rate of the purge stream will be 4 kmole/hr 5 kmole/hr 6 kmole/hr 3 kmole/hr 4 kmole/hr 5 kmole/hr 6 kmole/hr 3 kmole/hr ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Na₂SO₄. 10H₂O crystals are formed by cooling 100 Kg of 30% by weight aqueous solution of Na₂SO₄. The final concentration of the solute in the solution is 10%. The weight of crystals is 45.35 20 32.2 58.65 45.35 20 32.2 58.65 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Which of the following holds good for a solution obeying Raoult's law (i.e., an ideal solution) (where, ΔH = heat of mixing, and ΔV = volume change on mixing ) ? Both B and C ΔH = 0 ΔV = 0 ΔH = 1 (+ ve)and Δ V = -ve Both B and C ΔH = 0 ΔV = 0 ΔH = 1 (+ ve)and Δ V = -ve ANSWER DOWNLOAD EXAMIANS APP
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