Steam Boilers, Engines, Nozzles and Turbines The critical pressure ratio (p₂/p₁) is given by (p₂/p₁) = [(n - 1)/2] n + (1/n) (p₂/p₁) = [(n + 1)/2] n - (1/n) (p₂/p₁) = [2/(n + 1)] n/(n-1) (p₂/p₁) = [2/(n - 1)] n/(n + 1) (p₂/p₁) = [(n - 1)/2] n + (1/n) (p₂/p₁) = [(n + 1)/2] n - (1/n) (p₂/p₁) = [2/(n + 1)] n/(n-1) (p₂/p₁) = [2/(n - 1)] n/(n + 1) ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines The efficiency of an impulse turbine is maximum when (where Vb = Blade speed, V = Absolute velocity of steam entering the blade, and α = Nozzle angle) Vb = V cosα Vb = 0.5 V cosα Vb = V² cosα Vb = 0.5 V² cosα Vb = V cosα Vb = 0.5 V cosα Vb = V² cosα Vb = 0.5 V² cosα ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines At very low temperature, the melting and boiling temperatures become equal. This temperature is 373°K 0°K 303°K 273.16°K 373°K 0°K 303°K 273.16°K ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines Which of the following boiler works on a forced circulation of water? Lamont boiler All of these Benson boiler Loeffler boiler Lamont boiler All of these Benson boiler Loeffler boiler ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines Gradually increasing temperature of flue gases at inlet to chimney for given steam outputs is an indication of Fouling of heat transfer surfaces Raising of steam temperature Higher effectiveness of boiler High calorific value coal being burnt Fouling of heat transfer surfaces Raising of steam temperature Higher effectiveness of boiler High calorific value coal being burnt ANSWER DOWNLOAD EXAMIANS APP
Steam Boilers, Engines, Nozzles and Turbines 100% efficiency of a thermal cycle cannot be achieved because of Leakage Non availability of ideal substance It is not possible to achieve 0°K temperature Frictional losses Leakage Non availability of ideal substance It is not possible to achieve 0°K temperature Frictional losses ANSWER DOWNLOAD EXAMIANS APP
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