Area Problems The Area of a square is 50 sq. units. Then the area of the circle drawn on its diagonal is? None of theas 50? sq. units 25? sq. units 100? sq. units None of theas 50? sq. units 25? sq. units 100? sq. units ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = (Diagonal)2 / 2 = 50? Diagonal = 10 units ? Radius of required circle = 5 unitsIts area = [? x (5)2 ] cm2= 25? units2
Area Problems A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? 34 68 88 40 34 68 88 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft
Area Problems A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is: Rs. 456 Rs. 558 Rs. 568 Rs. 458 Rs. 456 Rs. 558 Rs. 568 Rs. 458 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area to be plastered = [2(l + b) x h] + (l x b) = {[2(25 + 12) x 6] + (25 x 12)} m2 = (444 + 300) m2 = 744 m2. ∴ Cost of plastering = Rs. ❨ 744 x 75 ❩ = Rs. 558
Area Problems The inner circumference of a circular race track, 14 m wide, is 440 m. Find radius of the outer circle 44 22 84 33 44 22 84 33 ANSWER DOWNLOAD EXAMIANS APP
Area Problems The area of a right angled triangle is 10 sq cm. If its perpendicular is equal to 20 cm, find its base. 1 cm 3 cm 2 cm 4 cm 1 cm 3 cm 2 cm 4 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, area = 10 sq cm, perpendicular = 20 cm and base = ? area = (base x Perpendicular) / 2 ? 10 = (base x 20) / 2 ? base = 1 cm
Area Problems The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and the breadth is increased by 5 cm, the area of the rectangle is increased by 75 cm 2 . Therefore , the length of the rectangle is? 30 cm 20 cm 40 cm 50 cm 30 cm 20 cm 40 cm 50 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b, length = 2b? Area of rectangle = 2b x b = 2b2As per question. ? (2b - 5 ) (b + 5 ) = 2b2 + 75? 5b = 75 + 25? 5b = 100? b = 100 / 5 = 20Hence, length of the rectangle =2b = 2 x 20 = 40 cm.
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