Engineering Mechanics The acceleration of a body sliding down an inclined surface is g cosθ g sinθ g tanθ None of these g cosθ g sinθ g tanθ None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is bh3/12 bh3/4 bh3/36 bh3/8 bh3/12 bh3/4 bh3/36 bh3/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If n = number of members and y = number of joints, then for a perfect frame, n = ? 43832 43892 43864 43865 43832 43892 43864 43865 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The rate of doing work is known as Potential energy Kinetic energy Power None of these Potential energy Kinetic energy Power None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) ANSWER DOWNLOAD EXAMIANS APP
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