Introduction to SQL Table employee has 10 records. It has a non-NULL SALARY column which is also UNIQUE.The SQL statementSELECT COUNT(*) FROM employee WHERE SALARY > ALL (SELECT SALARY FROM EMPLOYEE);prints 5 10 9 0 5 10 9 0 ANSWER DOWNLOAD EXAMIANS APP
Introduction to SQL SQL provides the AS keyword, which can be used to assign meaningful column names to the results of queries using the SQL built-in functions. False True False True ANSWER DOWNLOAD EXAMIANS APP
Introduction to SQL The command to eliminate a table from a database is: UPDATE TABLE CUSTOMER; DELETE TABLE CUSTOMER; REMOVE TABLE CUSTOMER; DROP TABLE CUSTOMER; UPDATE TABLE CUSTOMER; DELETE TABLE CUSTOMER; REMOVE TABLE CUSTOMER; DROP TABLE CUSTOMER; ANSWER DOWNLOAD EXAMIANS APP
Introduction to SQL How to select all data from student table starting the name from letter 'r'? SELECT * FROM student WHERE name LIKE '_r%'; SELECT * FROM student WHERE name LIKE '%r%'; SELECT * FROM student WHERE name LIKE 'r%'; SELECT * FROM student WHERE name LIKE '%r'; SELECT * FROM student WHERE name LIKE '_r%'; SELECT * FROM student WHERE name LIKE '%r%'; SELECT * FROM student WHERE name LIKE 'r%'; SELECT * FROM student WHERE name LIKE '%r'; ANSWER DOWNLOAD EXAMIANS APP
Introduction to SQL Which of the following query finds the name of the sailors who have reserved at least two boats? SELECT DISTINCT s.sname FROM sailors s, reserves r1, reserves r2 WHERE s.sid = r1.sid AND r1.sid = r2.sid AND r1.bid <> r2.bid SELECT DISTINCT s.sname FROM sailors s, reserves r1, reserves r2 WHERE s.sid = r1.sid AND COUNT(r1.bid) > r2.bid SELECT DISTINCT s.sname FROM sailors s, reserves r1, reserves r2 WHERE s.sid = r1.sid AND r1.sid = r2.sid AND r1.bid ≠ r2.bid All of these SELECT DISTINCT s.sname FROM sailors s, reserves r1, reserves r2 WHERE s.sid = r1.sid AND r1.sid = r2.sid AND r1.bid <> r2.bid SELECT DISTINCT s.sname FROM sailors s, reserves r1, reserves r2 WHERE s.sid = r1.sid AND COUNT(r1.bid) > r2.bid SELECT DISTINCT s.sname FROM sailors s, reserves r1, reserves r2 WHERE s.sid = r1.sid AND r1.sid = r2.sid AND r1.bid ≠ r2.bid All of these ANSWER DOWNLOAD EXAMIANS APP
Introduction to SQL There is an equivalent join expression that can be substituted for all subquery expressions. False True False True ANSWER DOWNLOAD EXAMIANS APP
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