Let the number be 10x + y∴ 3x = 4y ......(1)From (I),x + y = 14 .....(2)Solving equations (1) and (2),x = 8, y = 6∴ Number = 86 From (II)y = 75/100 x x ∴ 3x = 4y.Which is the same as eqn (1)
Let the present age of the father be 'x' and that of the son be 'y'. Then x/y = 8/3∴ 3x = 8y Further, x + 12/y + 12 = 2/1 ∴ x + 12 = 2y + 24 ∴ x - 2y = 12 ......(ii)From eqn (i) and (ii), x = 48, y = 18 ∴ sum = 66 yrs.