Chemical Engineering Thermodynamics Standard temperature and pressure (S.T.P.) is 0°C and 1 kgf/cm² 15°C and 750 mm Hg 15°C and 1 kgf/cm² 0°C and 750 mm Hg 0°C and 1 kgf/cm² 15°C and 750 mm Hg 15°C and 1 kgf/cm² 0°C and 750 mm Hg ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Internal energy of an ideal gas None of these Increases with increase in pressure Decreases with increase in temperature Is independent of temperature None of these Increases with increase in pressure Decreases with increase in temperature Is independent of temperature ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Lenz's law results from the law of conservation of Mass Momentum Energy None of these Mass Momentum Energy None of these ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics When a system in equilibrium is subjected to a change in temperature, pressure or concentration, the equilibrium is displaced in a direction which tends to undo the effect of the change. This is called the Law of corresponding state Le-Chatelier principle Arrehenius hypothesis Kopp's rule Law of corresponding state Le-Chatelier principle Arrehenius hypothesis Kopp's rule ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Which of the following has the minimum value of COP for a given refrigeration effect? Vapour-compression process with a reversible expansion engine Reverse Carnot cycle Air refrigeration cycle Ordinary vapour-compression cycle Vapour-compression process with a reversible expansion engine Reverse Carnot cycle Air refrigeration cycle Ordinary vapour-compression cycle ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics On a P-V diagram of an ideal gas, suppose a reversible adiabatic line intersects a reversible isothermal line at point A. Then at a point A, the slope of the reversible adiabatic line (∂P/∂V)S and the slope of the reversible isothermal line (∂P/∂V)T are related as (where, y = Cp/Cv) ) (∂P/∂V)S = 1/y(∂P/∂V)T (∂P/∂V)S = [(∂P/∂V)T]Y (∂P/∂V)S = (∂P/∂V)T (∂P/∂V)S = y(∂P/∂V)T (∂P/∂V)S = 1/y(∂P/∂V)T (∂P/∂V)S = [(∂P/∂V)T]Y (∂P/∂V)S = (∂P/∂V)T (∂P/∂V)S = y(∂P/∂V)T ANSWER DOWNLOAD EXAMIANS APP
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