Concrete Technology and Design of Concrete Structures Shrinkage of concrete depends upon i) humidity of atmosphere ii) passage of time iii) stress The correct answer is (i) and (ii) All (i), (ii) and (iii) (ii) and (iii) only (iii) (i) and (ii) All (i), (ii) and (iii) (ii) and (iii) only (iii) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The critical section for finding maximum bending moment for footing under masonry wall is located at the edge of the wall halfway between the middle and edge of the wall at the middle of the wall at a distance equal to effective depth of footing from the edge of the wall at the edge of the wall halfway between the middle and edge of the wall at the middle of the wall at a distance equal to effective depth of footing from the edge of the wall ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In a counterfort retaining wall, the main reinforcement in the stem at mid span is provided on both front face and inner face inner face only None of these front face only both front face and inner face inner face only None of these front face only ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Finer grinding of cement both (a) and (b) affects only the early development of strength does not affect the strength affects only the ultimate strength both (a) and (b) affects only the early development of strength does not affect the strength affects only the ultimate strength ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Shrinkage of concrete depends uponi) humidity of atmosphereii) passage of timeiii) stress The correct answer is All (i), (ii) and (iii) only (iii) (i) and (ii) (ii) and (iii) All (i), (ii) and (iii) only (iii) (i) and (ii) (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fc5>fcr>fC fcr fcr>fcs>fc. tcr – rcs = tct fc5>fcr>fC fcr fcr>fcs>fc. tcr – rcs = tct ANSWER DOWNLOAD EXAMIANS APP