Analog Electronics Reverse saturation electric current in a silicon pn junction diode nearly doubles for very 6° rise in temperature. 10° rise in temperature. 5° rise in temperature. 2° rise in temperature. 6° rise in temperature. 10° rise in temperature. 5° rise in temperature. 2° rise in temperature. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics Binary Logic is mainly based on arithmetic operation and logical operations subtraction operations addition operations both A and B logical operations subtraction operations addition operations both A and B ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics The base-emitter voltage of an ideal transistor is 0.3 V. 0.7 V. 1 V. 0 V. 0.3 V. 0.7 V. 1 V. 0 V. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics Given (135)x + (144)x = (323)x what is the value of base x? 3 4 5 6 3 4 5 6 ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics The current gain of a pnp transistor is the collector current divided by the emitter current. the negative of the npn current gain. near zero. the ratio of collector current to emitter current. the collector current divided by the emitter current. the negative of the npn current gain. near zero. the ratio of collector current to emitter current. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics An npn BJT has gm=38mA/v, cµ =10¯14 F, cπ =10¯13F and DC current gain β0=90.For this transistor fT & fβ are fT =1.33 x 1012 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.64 x 108 Hz fT =1.64 x 108 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.33 x 1012 Hz fT =1.33 x 1012 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.64 x 108 Hz fT =1.64 x 108 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.33 x 1012 Hz ANSWER DOWNLOAD EXAMIANS APP
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