Engineering Thermodynamics Relation between cp and cv is given by (where cp = Specific heat at constant pressure, cv = Specific heat at constant volume, γ = cp/cv, known as adiabatic index, and R = Gas constant) cv/ cp =R cv = R/ γ-1 Both (B) and (C) cp - cv = R cv/ cp =R cv = R/ γ-1 Both (B) and (C) cp - cv = R ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The heating of gas at constant volume is governed by Charles' law Gay-Lussac law Avogadro's law Boyle's law Charles' law Gay-Lussac law Avogadro's law Boyle's law ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The calorific value of gaseous fuel is expressed in kJ kJ/m3 kJ/m2 kJ/kg kJ kJ/m3 kJ/m2 kJ/kg ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Carnot cycle efficiency is maximum when Difference between initial and final temperature is 0°K Final temperature is 0°K Final temperature is 0°C Initial temperature is 0°K Difference between initial and final temperature is 0°K Final temperature is 0°K Final temperature is 0°C Initial temperature is 0°K ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics According to Avogadro's law, for a given pressure and temperature, each molecule of a gas Occupies volume inversely proportional to its specific weight Occupies same volume Occupies volume inversely proportional to its molecular weight Occupies volume proportional to its specific weight Occupies volume inversely proportional to its specific weight Occupies same volume Occupies volume inversely proportional to its molecular weight Occupies volume proportional to its specific weight ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of the product of molecular weight and the gas characteristic constant for all the gases in S.I. units is 848 J/kmol °K 83.14 J/kmol °K 735 J/kmol °K 29.27 J/kmol °K 848 J/kmol °K 83.14 J/kmol °K 735 J/kmol °K 29.27 J/kmol °K ANSWER DOWNLOAD EXAMIANS APP
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