One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH₄ + 2O₂ → CO₂ + 2H₂O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. If the average specific heat of all the gases/vapour is 40 J/mole.K, the maximum temperature rise of the exhaust gases in °C would be approximately equal to

Stoichiometry
One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH₄ + 2O₂ → CO₂ + 2H₂O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. If the average specific heat of all the gases/vapour is 40 J/mole.K, the maximum temperature rise of the exhaust gases in °C would be approximately equal to

1225

1335

1735

1525

1225

1335

1735

1525

ANSWER DOWNLOAD EXAMIANS APP

Stoichiometry
An ideal gas can be liquified, because

Its molecular size is very small

It gets solidified directly without becoming liquid

Forces operative between its molecules are negligible

Its critical temperature is more than 0°C

Its molecular size is very small

It gets solidified directly without becoming liquid

Forces operative between its molecules are negligible

Its critical temperature is more than 0°C

ANSWER DOWNLOAD EXAMIANS APP

Stoichiometry
1m³ is approximately equal to

4.5 ft³

4.5 litres

35 ft³

28 litres

4.5 ft³

4.5 litres

35 ft³

28 litres

ANSWER DOWNLOAD EXAMIANS APP

Stoichiometry
Degrees of freedom will be equal to the number of components for a system comprising of

Only soluble liquid components

None of these

Partially miscible two liquid components system having two phases

Two liquid components and one solute (soluble in both the liquids)

Only soluble liquid components

None of these

Partially miscible two liquid components system having two phases

Two liquid components and one solute (soluble in both the liquids)

ANSWER DOWNLOAD EXAMIANS APP

Stoichiometry
The heat of solution depends upon the

All of these

Concentration of solution

Nature of solute

Nature of solvent

All of these

Concentration of solution

Nature of solute

Nature of solvent

ANSWER DOWNLOAD EXAMIANS APP

Stoichiometry
Unrestrained expansion of an ideal gas does not result in its cooling due to the reason that the gas molecules

Do not exert attractive force on each other

Are above the inversion temperature

Do work equal to loss in kinetic energy

Do not lose energy on collision

Do not exert attractive force on each other

Are above the inversion temperature

Do work equal to loss in kinetic energy

Do not lose energy on collision

ANSWER DOWNLOAD EXAMIANS APP

Stoichiometry

Stoichiometry An ideal gas can be liquified, because

Stoichiometry 1m³ is approximately equal to

Stoichiometry Degrees of freedom will be equal to the number of components for a system comprising of

Stoichiometry The heat of solution depends upon the

Stoichiometry Unrestrained expansion of an ideal gas does not result in its cooling due to the reason that the gas molecules

Stoichiometry
An ideal gas can be liquified, because

Stoichiometry
1m³ is approximately equal to

Stoichiometry
Degrees of freedom will be equal to the number of components for a system comprising of

Stoichiometry
The heat of solution depends upon the

Stoichiometry
Unrestrained expansion of an ideal gas does not result in its cooling due to the reason that the gas molecules