Applied Mechanics and Graphic Statics Minimum potential energy of a system will be in the position of Stable equilibrium Unstable equilibrium All of these Neutral equilibrium Stable equilibrium Unstable equilibrium All of these Neutral equilibrium ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of Applied Mechanics and Graphic Statics mcq question image (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angle of projection for a range is equal to the distance through which the particle would have fallen in order to acquire a velocity equal to the velocity of projection, will be 30° 75° 60° 45° 30° 75° 60° 45° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body A of mass 6.6 kg which is lying on a horizontal platform 4.5 m from its edge is connected to the end of a light string whose other end is supporting a body of mass 3.2 kg as shown in below figure. If the friction between the platform and the body A is 1/3, the acceleration is 0.75 m/sec² 1.25 m/sec² 0.5 m/sec² 1.00 m/sec² 0.75 m/sec² 1.25 m/sec² 0.5 m/sec² 1.00 m/sec² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 2gh v = 1/√(2gh) v = 2gh² v = √(2gh) v = 2gh v = 1/√(2gh) v = 2gh² v = √(2gh) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The dimensions of centrifugal force are M’L’T2 M’L’T1 M’L-‘T2 M1 L2 T2 M’L’T2 M’L’T1 M’L-‘T2 M1 L2 T2 ANSWER DOWNLOAD EXAMIANS APP
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