Alligation or Mixture problems In what proportion water must be added to spirit to gain 20% by selling it at the cost price? 1:7 1:6 1:5 1:8 1:7 1:6 1:5 1:8 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems In what ratio should two varieties of sugar at Rs.18 per kg and Rs.24 Kg be mixed together to get a mixture whose cost is Rs.20 per kg? 1:2 2:1 3:1 1:3 1:2 2:1 3:1 1:3 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems Three bottles of equal capacity containing mixture of milk and water in ratio 2 : 5, 3 : 4 and 4 : 5 respectively. These three bottles are emptied into a large bottle. What will be the ratio of milk and water respectively in the large bottle? 73 : 106 73 : 113 73 : 189 73 : 116 73 : 106 73 : 113 73 : 189 73 : 116 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems A person has Rs. 5000. He invests a part of it at 3% per annum and the remainder at 8% per annum simple interest. His total income in 3 years is Rs. 750. Find the sum invested at different rates of interest. Rs. 3000 and Rs. 2000 Rs. 2500 and Rs. 2500 Rs. 2750 and Rs. 2250 Rs. 2000 and Rs. 3000 Rs. 3000 and Rs. 2000 Rs. 2500 and Rs. 2500 Rs. 2750 and Rs. 2250 Rs. 2000 and Rs. 3000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Average rate of interest = (100 * 750) / (5000 * 3) = 5% per annual Investment at 3% per annual = 3 / (3 + 2) × 5000 = Rs. 3000 Investment at 8% per annual = 2 / (3 + 2) × 5000 = Rs. 2000
Alligation or Mixture problems The ratio of milk and water in three samples is 1 : 3, 3 : 5 and 11 : 5. A mixture containing equal quantities of all three samples is made. What will be the ratio of milk and water in the new mixture? 7 : 9 15 : 13 5 : 7 9 : 11 7 : 9 15 : 13 5 : 7 9 : 11 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container? 87.62 lit 87.51 lit 88.01 lit 87.48 lit 87.62 lit 87.51 lit 88.01 lit 87.48 lit ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For these type of problems, Quantity of Diesel remained = q 1 - p q n Here p = 12 , q = 120 => 120 1 - 12 120 3 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.
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