Chemical Engineering Thermodynamics In an irreversible process Tds - dE + dW< 0 DE - dW - Tds = 0 Tds = dE - dW = 0 Tds - dT + dW< 0 Tds - dE + dW< 0 DE - dW - Tds = 0 Tds = dE - dW = 0 Tds - dT + dW< 0 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Joule-Thomson co-efficient for a perfect gas is Positive Zero Negative None of these Positive Zero Negative None of these ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics A large iceberg melts at the base, but not at the top, because of the reason that Due to the high pressure at the base, its melting point reduces Ice at the base contains impurities which lowers its melting point The iceberg remains in a warmer condition at the base All of these Due to the high pressure at the base, its melting point reduces Ice at the base contains impurities which lowers its melting point The iceberg remains in a warmer condition at the base All of these ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The value of Joule-Thomson co-efficient, in case where cooling occurs after the throttling process is +ve ∞ -ve +ve ∞ -ve ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics A gas has a volume of 27.3 c.c. at 0°C. Its volume at 10°C (if pressure remains unchanged) will be __________ c.c. 28.3 273 283 2.73 28.3 273 283 2.73 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Fugacity and pressure are numerically equal, when the gas is At low temperature In standard state At high pressure In ideal state At low temperature In standard state At high pressure In ideal state ANSWER DOWNLOAD EXAMIANS APP
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