Chemical Engineering Thermodynamics In an irreversible process Tds = dE - dW = 0 DE - dW - Tds = 0 Tds - dT + dW< 0 Tds - dE + dW< 0 Tds = dE - dW = 0 DE - dW - Tds = 0 Tds - dT + dW< 0 Tds - dE + dW< 0 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Air enters an adiabatic compressor at 300K. The exit temperature for a compression ratio of 3, assuming air to be an ideal gas (Y = Cp/Cv = 7/5) and the process to be reversible, is 300(33/7) 300(32/7) 300(33/5) 300(35/7) 300(33/7) 300(32/7) 300(33/5) 300(35/7) ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Entropy of an ideal gas depends upon its Pressure Temperature Both A & B Neither A nor B Pressure Temperature Both A & B Neither A nor B ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Van Laar equation deals with the activity co-efficients in Azeotropic mixture only None of these Ternary solutions Binary solutions Azeotropic mixture only None of these Ternary solutions Binary solutions ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The free energy change for a chemical reaction is given by (where, K = equilibrium constant) -RT lnK T lnK -R lnK RT lnK -RT lnK T lnK -R lnK RT lnK ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics A large iceberg melts at the base, but not at the top, because of the reason that Ice at the base contains impurities which lowers its melting point The iceberg remains in a warmer condition at the base All of these Due to the high pressure at the base, its melting point reduces Ice at the base contains impurities which lowers its melting point The iceberg remains in a warmer condition at the base All of these Due to the high pressure at the base, its melting point reduces ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS