Electronic Principles In a step-down transformer, which is larger? Neither Impossible to say Secondary voltage Primary voltage None of these Neither Impossible to say Secondary voltage Primary voltage None of these ANSWER DOWNLOAD EXAMIANS APP
Electronic Principles The value of a capacitor can be made larger by: increasing the voltage applied to the plates decreasing the area of the plates increasing the frequency of the applied voltage increasing the area of the plates None of these increasing the voltage applied to the plates decreasing the area of the plates increasing the frequency of the applied voltage increasing the area of the plates None of these ANSWER DOWNLOAD EXAMIANS APP
Electronic Principles When a parallel RLC circuit is operating at its resonant frequency: inductive reactance is greater than the capacitive reactance capacitive reactance is greater than the inductive reactance the difference between inductive and capacitive reactance is equal to the resistance None of these inductive reactance is equal to the capacitive reactance inductive reactance is greater than the capacitive reactance capacitive reactance is greater than the inductive reactance the difference between inductive and capacitive reactance is equal to the resistance None of these inductive reactance is equal to the capacitive reactance ANSWER DOWNLOAD EXAMIANS APP
Electronic Principles Assuming 100% efficiency, what is the power being consumed at the secondary winding of the transformer described in question 91? 1000 W 20 W 100 W None of these 200 W 1000 W 20 W 100 W None of these 200 W ANSWER DOWNLOAD EXAMIANS APP
Electronic Principles The peak value of a sine waveform is: the amplitude at 70.7% of the maximum value the amplitude at 90% of the maximum value the maximum positive or negative value None of these the amplitude at 1.41 times the maximum value the amplitude at 70.7% of the maximum value the amplitude at 90% of the maximum value the maximum positive or negative value None of these the amplitude at 1.41 times the maximum value ANSWER DOWNLOAD EXAMIANS APP
Electronic Principles The voltage across a 1N4001 is 0.93V when the current is 1A. What is the power dissipation of the diode for these values? 0.93 W 0.041666666666667 0.93 V 9.3 W None of these 0.93 W 0.041666666666667 0.93 V 9.3 W None of these ANSWER DOWNLOAD EXAMIANS APP
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