Engineering Mechanics If the body falls freely under gravity, then the gravitational acceleration is taken as -9.8 m/s2 -8.9 m/s2 +9.8 m/s2 +8.9 m/s2 -9.8 m/s2 -8.9 m/s2 +9.8 m/s2 +8.9 m/s2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Which of the following statement is incorrect? The ratio of the limiting friction to the normal reaction is called coefficient of friction A machine whose efficiency is 100% is known as an ideal machine A force acting in the opposite direction to the motion of the body is called force of friction The velocity ratio of a machine is the ratio of load lifted to the effort applied The ratio of the limiting friction to the normal reaction is called coefficient of friction A machine whose efficiency is 100% is known as an ideal machine A force acting in the opposite direction to the motion of the body is called force of friction The velocity ratio of a machine is the ratio of load lifted to the effort applied ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In a screw jack, the effort required to lift the load is given by (where W = Load lifted, α = Helix angle, and φ = Angle of friction.) P = W cos (α + φ) P = W tan (φ - α) P = W tan (α - φ) P = W tan (α + φ) P = W cos (α + φ) P = W tan (φ - α) P = W tan (α - φ) P = W tan (α + φ) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The forces, which meet at one point, but their lines of action do not lie in a plane, are called Coplanar non-concurrent forces Intersecting forces Non-coplanar non-concurrent forces Non-coplanar concurrent forces Coplanar non-concurrent forces Intersecting forces Non-coplanar non-concurrent forces Non-coplanar concurrent forces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
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