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Engineering Mechanics

Engineering Mechanics
If the body falls freely under gravity, then the gravitational acceleration is taken as

-9.8 m/s2
+9.8 m/s2
-8.9 m/s2
+8.9 m/s2

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Engineering Mechanics
If a number of forces are acting at a point, their resultant will be inclined at an angle 'θ' with the horizontal, such that

tanθ = ΣH/ΣV
tanθ = ΣV/ΣH
tanθ = ΣV × ΣH
tanθ = √(ΣV + ΣH)

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Engineering Mechanics
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = IG / Ah2
IP = Ah2 / IG
IP = IG + Ah2
IP = IG - Ah2

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Engineering Mechanics
The moment of inertia of a square of side (a) about an axis through its center of gravity is

a4/8
a4/36
a4/12
a4/4

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Engineering Mechanics
A spherical body is symmetrical about its perpendicular axis. According to Routh's rule, the moment of inertia of a body about an axis passing through its centre of gravity is (where, M = Mass of the body, and S = Sum of the squares of the two semi-axes.)

MS/3
MS/5
MS/4
None of these

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Engineering Mechanics
The unit of angular acceleration is

m/s
N-m
rad/s2
m/s2

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MORE MCQ ON Engineering Mechanics

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