If the sum of the digits of a number is divisible by 9, the number will be divisible by 9.2 + 6 + 3 + 2 + 5 + 1 = 19The nearest multiple of 9 is 18.19 - 18 = 1.
Let the consecutive even numbers be A = 2x, B = 2x + 2, C = 2x + 4, D = 2x + 6 and E = 2x + 8= A + B + C + D + E = 130= 10x + 20 = 130∴ x = 130 - 20/10 = 11Therefore, product of A and E= 22 x 30 = 660
EXAMIANS