Chemical Reaction Engineering If 'n' is the order of reaction, then unit of rate constant is None of these 1/(time)(concentration)n - 1 (time)n - 1 (concentration) (time)-1 (concentration)n - 1 None of these 1/(time)(concentration)n - 1 (time)n - 1 (concentration) (time)-1 (concentration)n - 1 ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering An isothermal aqueous phase reversible reaction, P ⇋ R, is to be carried out in a mixed flow reactor. The reaction rate in k.mole/m³ .h is given by, r = 0.5CP - 0.125CR. A stream containing only P enters the 0.80 2.67 1.33 1.60 0.80 2.67 1.33 1.60 ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering A catalyst in a chemical reaction __________ free energy change in the reaction. Neither A nor B Either A or B; depends on the type of catalyst Increases Decreases Neither A nor B Either A or B; depends on the type of catalyst Increases Decreases ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering A space velocity of 5 hr⁻¹ means that A fixed conversion of a given batch of feed takes 5 hours Cent per cent conversion can be achieved in at least 5 hours Five reactor volumes of feed (at specified conditions) are being fed into the reactor per hour After every 5 hours, reactor is being filled with the feed A fixed conversion of a given batch of feed takes 5 hours Cent per cent conversion can be achieved in at least 5 hours Five reactor volumes of feed (at specified conditions) are being fed into the reactor per hour After every 5 hours, reactor is being filled with the feed ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering If the pore diffusion controls in a catalytic reaction, the apparent activation energy Ea is equal to The intrinsic activation energy E ED/2 (E + ED)/2 (E + ED) where ED is activation due to diffusion The intrinsic activation energy E ED/2 (E + ED)/2 (E + ED) where ED is activation due to diffusion ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering A pollutant P degrades according to first order kinetics. An aqueous stream containing P at 2 kmole/m³ and volumetric flow rate 1m³ /h requires a mixed flow reactor of volume V to bring down the pollutant level to 0.5 kmole/m³ . The inlet concentration of the pollutant is now doubled and the volumetric flow rate is tripled. If the pollutant level is to be brought down to the same level of 0.5 kmole/m³ , the volume of the mixed flow reactor should be increased by a factor of 7 44015 6 3 7 44015 6 3 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS