Chemical Reaction Engineering Higher free energy of activation of a chemical reaction (at a given temperature) implies Both B and C Slower rate of reaction Higher rate of reaction Higher equilibrium conversion Both B and C Slower rate of reaction Higher rate of reaction Higher equilibrium conversion ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering In case of staged packed bed reactors carrying out exothermic reaction, use All of these Cold shot operations for a dilute solution requiring large preheating to bring the stream upto the reaction temperature High recycle for pure gas Plug flow for dilute liquid requiring no large preheating of feed All of these Cold shot operations for a dilute solution requiring large preheating to bring the stream upto the reaction temperature High recycle for pure gas Plug flow for dilute liquid requiring no large preheating of feed ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering For the liquid phase zero order irreversible reaction A → B, the conversion of A in a CSTR is found to be 0.3 at a space velocity of 0.1min⁻¹ . What will be the conversion for a PFR with a space velocity of 0.2 min⁻¹? Assume that all the other operating conditions are the same for CSTR and PFR. 0.3 0.9 0.6 0.15 0.3 0.9 0.6 0.15 ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering An imbalanced chemical reaction equation is against the law of Multiple proportion Constant proportion None of these Conservation of mass Multiple proportion Constant proportion None of these Conservation of mass ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering A catalyst promoter Itself has very high activity Acts as a catalyst support Improves the activity of a catalyst All of these Itself has very high activity Acts as a catalyst support Improves the activity of a catalyst All of these ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering A first order gaseous phase reaction is catalysed by a non-porous solid. The kinetic rate constant and the external mass transfer co-efficients are k and kg respectively. The effective rate constant (keff) is given by 1/keff = 1/k + 1/kg keff = (kkg)1/2 keff = (k+ kg)/2 keff = k + kg 1/keff = 1/k + 1/kg keff = (kkg)1/2 keff = (k+ kg)/2 keff = k + kg ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS