Chemical Reaction Engineering Half life period of a chemical reaction is None of these The time required to reduce the concentration of the reacting substance to half its initial value Half of the residence time of a reaction Half of the space time of a reaction None of these The time required to reduce the concentration of the reacting substance to half its initial value Half of the residence time of a reaction Half of the space time of a reaction ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering Collision theory gives the rate constant for bimolecular reaction as K α eE/RT K α √T.e-E/RT None of these K α e-E/RT K α eE/RT K α √T.e-E/RT None of these K α e-E/RT ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering Considering the endotheomic dissociation of CaCO₃ in a closed vessel (CaCO₃ ⇋ CaO + CO₂), the pressure of CO₂ increases, if A catalyst is added None of these An inert gas is pumped keeping the temperature constant The temperature is increased A catalyst is added None of these An inert gas is pumped keeping the temperature constant The temperature is increased ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering 6 gm of carbon is burnt with an amount of air containing 18 gm oxygen. The product contains 16.5 gms CO₂ and 2.8 gms CO besides other constituents. What is the degree of conversion on the basis of disappearance of limiting reactant? 0.95 1 0.75 0.2 0.95 1 0.75 0.2 ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering The following gas phase reactions are carried out isothermally in a CSTR.A → 2R ; r₁ = K₁pA ;K₁ = 20mole/(sec.m³ bar)A → 3S ; r₂ = K₂ pA ;K₂ = 40mole/ (sec.m³ .bar)What is the maximum possible value of FR(mole/sec.) ? 43864 43833 43832 2 43864 43833 43832 2 ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering A first order gaseous phase reaction is catalysed by a non-porous solid. The kinetic rate constant and the external mass transfer co-efficients are k and kg respectively. The effective rate constant (keff) is given by keff = k + kg keff = (kkg)1/2 keff = (k+ kg)/2 1/keff = 1/k + 1/kg keff = k + kg keff = (kkg)1/2 keff = (k+ kg)/2 1/keff = 1/k + 1/kg ANSWER DOWNLOAD EXAMIANS APP
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