Chemical Reaction Engineering
For the reversible reaction A ⇋ 2B, if the equilibrium constant K is 0.05 mole/litre; starting from initially 2 moles of A and zero moles of B, how many moles will be formed at equilibrium?

0.637
0.152
0.253
0.338

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Chemical Reaction Engineering
The rate expression for a heterogenous catalytic reaction is given by, - rA = K.KA PA(1 + KA.PA + Kr.PR), where K is surface reaction rate constant and KA and KR are absorption equilibrium constants of A and R respectively. If KR PR >> (1 + KA PA), the apparent activation energy EA is equal to (given E is the activation energy for the reaction and ΔHR and ΔHA are the activation energies of adsorption of R and A)

ΔHA + ΔHR
E
E + ΔHA
E + ΔHA - ΔHR

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