Chemical Reaction Engineering For the reversible reaction A ⇋ 2B, if the equilibrium constant K is 0.05 mole/litre; starting from initially 2 moles of A and zero moles of B, how many moles will be formed at equilibrium? 0.253 0.637 0.152 0.338 0.253 0.637 0.152 0.338 ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering In case of staged packed bed reactors carrying out exothermic reaction, use High recycle for pure gas All of these Cold shot operations for a dilute solution requiring large preheating to bring the stream upto the reaction temperature Plug flow for dilute liquid requiring no large preheating of feed High recycle for pure gas All of these Cold shot operations for a dilute solution requiring large preheating to bring the stream upto the reaction temperature Plug flow for dilute liquid requiring no large preheating of feed ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering Mean residence time is equal to the space time, when The temperature, pressure and the density of reaction mixture remains constant throughout the reactor The feed rate is measured at temperature and pressure in the reactor All of these There is no change in number of moles in gaseous reaction The temperature, pressure and the density of reaction mixture remains constant throughout the reactor The feed rate is measured at temperature and pressure in the reactor All of these There is no change in number of moles in gaseous reaction ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering Enzymes (a protein) are catalysts found in organisms. Its efficiency of catalysing a reaction is due to its capacity to lower the activation energy of the reaction. The enzyme ptyalin used for food digestion is present in Blood Intestine Gland Saliva Blood Intestine Gland Saliva ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering Bulk diffusion in catalyst pore __________ with increase in pressure. Remains unchanged Increases exponentially Decreases Increases Remains unchanged Increases exponentially Decreases Increases ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering At a given temperature, K₁, K₂ and K3 are equilibrium constants for the following reactions 1, 2, 3 respectively. CH₄(g) + H₂O(g) ⇋ CO(g) + 3H₂(g), CO(g) + H₂O(g) ⇋ CO₂(g) + H₂(g) CH₄(g) + 2H₂O(g) ⇋ CO₂(g) + 4H₂(g) Then K₁, K₂ and K3 are related as: K3 = (K₁.K₂)0.5 K3(K₁+K₂)/2 K3 = K₁.K₂ K3 = (K₁.K₂)2 K3 = (K₁.K₂)0.5 K3(K₁+K₂)/2 K3 = K₁.K₂ K3 = (K₁.K₂)2 ANSWER DOWNLOAD EXAMIANS APP
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