Electric Circuits For the circuit shown below the value of R is adjusted so as to make the current in RL equal to zero. Calculate the value of R. 2 Ω. 3 Ω. 1 Ω. 4 Ω. 2 Ω. 3 Ω. 1 Ω. 4 Ω. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Twelve 6 Ω resistor used as edge to form a cube. The resistance between two diagonally opposite corner of the cube is 6 Ω. 5 / 6 Ω. 6 / 5 Ω. 5 Ω. 6 Ω. 5 / 6 Ω. 6 / 5 Ω. 5 Ω. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A external resistance R is connected to a cell of internal resistance r, then the current is maximum when None of these R < r. R = r. R > r. None of these R < r. R = r. R > r. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Say A point has an absolute potential of 40 V and point B has an absolute potential of - 10 V, then what will be the value of VBA ? 30 V. - 50 V. 50 V. none of above. 30 V. - 50 V. 50 V. none of above. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Constant K type HPF (high pass filter) having cut off frequency 12 KHz and nominal impedance Ro = 500 Ω Find shunt arm inductor L and series arm capacitance C for T and π section of HPF ? L = 0.0132 mH, C = 0.0132 μF. L = 3.316 mH, C = 0.0132 μF. None of these. L = 3.316 mH, C = 132 μF. L = 0.0132 mH, C = 0.0132 μF. L = 3.316 mH, C = 0.0132 μF. None of these. L = 3.316 mH, C = 132 μF. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The charge of an electron is - 1.675 × 10 - 27 Coulombs. - 1.602 × 10 - 19 Coulombs. - 9.109 × 10 - 31 Coulombs. - 1.672 × 10 - 27 Coulombs. - 1.675 × 10 - 27 Coulombs. - 1.602 × 10 - 19 Coulombs. - 9.109 × 10 - 31 Coulombs. - 1.672 × 10 - 27 Coulombs. ANSWER DOWNLOAD EXAMIANS APP
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