Compressors, Gas Turbines and Jet Engines For speed above 3000 km/hour, it is more advantageous to use Ramjet engine Turbojet engine Propellers Rockets Ramjet engine Turbojet engine Propellers Rockets ANSWER DOWNLOAD EXAMIANS APP
Compressors, Gas Turbines and Jet Engines The volumetric efficiency of a compressor Decreases with increase in compression ratio Decreases with decrease in compression ratio Increases with increase in compression ratio Increases with decrease in compression ratio Decreases with increase in compression ratio Decreases with decrease in compression ratio Increases with increase in compression ratio Increases with decrease in compression ratio ANSWER DOWNLOAD EXAMIANS APP
Compressors, Gas Turbines and Jet Engines Gas turbine cycle with regenerator Decreases heat loss is exhaust Increases thermal efficiency Allows high compression ratio Allows operation at very high altitudes Decreases heat loss is exhaust Increases thermal efficiency Allows high compression ratio Allows operation at very high altitudes ANSWER DOWNLOAD EXAMIANS APP
Compressors, Gas Turbines and Jet Engines Adiabatic compression is one in which Temperature rise follows a linear relationship Temperature during compression remains constant Work done is maximum No heat leaves or enters the compressor cylinder during compression Temperature rise follows a linear relationship Temperature during compression remains constant Work done is maximum No heat leaves or enters the compressor cylinder during compression ANSWER DOWNLOAD EXAMIANS APP
Compressors, Gas Turbines and Jet Engines The maximum compression ratio in an actual single stage axial flow compressor is of the order of 0.048611111111111 0.045138888888889 0.00070833333333333 0.043055555555556 0.048611111111111 0.045138888888889 0.00070833333333333 0.043055555555556 ANSWER DOWNLOAD EXAMIANS APP
Compressors, Gas Turbines and Jet Engines In n₁ and n₂ are the indices of compression for the first and second stage of compression, then the ratio of work-done on the first and second stages (W₁/W₂) with perfect intercooling is given by W₁/W₂ = n₂(n₁ - 1)/n₁(n₂ - 1) W₁/W₂ = n₁/n₂ W₁/W₂ = n₂/n₁ W₁/W₂ = n₁(n₂ - 1)/n₂(n₁ - 1) W₁/W₂ = n₂(n₁ - 1)/n₁(n₂ - 1) W₁/W₂ = n₁/n₂ W₁/W₂ = n₂/n₁ W₁/W₂ = n₁(n₂ - 1)/n₂(n₁ - 1) ANSWER DOWNLOAD EXAMIANS APP
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