Electromagnetic Field Theory For a linear electromagnetic circuit, which of the following statement is true? Field energy is equal to the co-energy. Field energy is greater than the co-energy. Co-energy is zero. Field energy is lesser than the co-energy. Field energy is equal to the co-energy. Field energy is greater than the co-energy. Co-energy is zero. Field energy is lesser than the co-energy. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory A rectangular waveguide is a Tube antenna to transmit and receive electromagnetic waves Hollow rectangular walled room carrying electromagnetic wave Hollow rectangular conducting tube through which electromagnetic waves can be propagat-ed Rectangular conducting wire to propagate electromagnetic waves Tube antenna to transmit and receive electromagnetic waves Hollow rectangular walled room carrying electromagnetic wave Hollow rectangular conducting tube through which electromagnetic waves can be propagat-ed Rectangular conducting wire to propagate electromagnetic waves ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory A conductor of length 1 metre moves at right angles to magnetic field of flux density 1 Wb/m2 with a velocity of 25 m/s. The induced emf in the conductor will be 50 V. 100 V. 75 V. 25 V. 50 V. 100 V. 75 V. 25 V. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory Mutual inductance between two magnetically coupled coils depends on all of above. permeability of core. cross sectional area of their common core. the number of their turns. all of above. permeability of core. cross sectional area of their common core. the number of their turns. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory The inductance of a long solenoid of length 1000 mm wound uniformly with 3000 turns on a cylindrical paper cable of 60 mm diameter is 3.2 mH. 3.2 µH. 32 mH. 3.2 H. 3.2 mH. 3.2 µH. 32 mH. 3.2 H. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory An inductor designed with 400 turns coil wound on an iron core of 16 cm2 cross sectional area and with a cut of air gap length of 1 mm. The coil is connected to a 230 V, 50 Hz supply. Neglected coil resistance, core loss, iron reluctance and leakage inductance. Find the current in the inductor. 9.04 A. 4.56 A. 2.28 A. 18.08 A. 9.04 A. 4.56 A. 2.28 A. 18.08 A. ANSWER DOWNLOAD EXAMIANS APP
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