Fractions and Decimals Find the integer which when decreased by 2 is 80 times the reciprocal of the same number 10 12 11 13 10 12 11 13 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the number be X Decreasing 2 from XX - 2 = 80 x (1/X)X^2 - 2X = 80X^2 -2x -80 = 0(X-10)(X+8) = 0x=10,-8X has two values, but among the given options X value should be 10
Fractions and Decimals ( .009 / ?) = .01 0.09 9 0.009 0.9 0.09 9 0.009 0.9 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let .009 / x = .01; Then x = .009 / .01=.9 / 1= .9
Fractions and Decimals (369.99)² = ? 1369 1369 x 10 None of these 1369 x 10² 1369 1369 x 10 None of these 1369 x 10² ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1369 x 10²
Fractions and Decimals If x/y = 0.3, then (2x - y)/(2x + y) = ? 0.5 0.25 0.5 0.15 0.5 0.25 0.5 0.15 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP x = 0.3y Then, (y - 2x)/(y + 2x)= y - 2(0.3y)/y + 2(0.3y)= y - 0.6y/y + 0.6y= 0.4y/1.6y= 0.4/1.6 = 0.25
Fractions and Decimals (.356 x .365 - 2 x .365 x .106 + .106 x .106) / (.632 x .632 + 2 x .632 x .368 +.368 x .368) = ? .625 62.5 6.25 .0625 .625 62.5 6.25 .0625 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(.356)² -2 x .356 x .106 + (.106)²] / [(.632)²+2 x .632 x .368 +(.368)²]= (a² -2ab + b²) / (c²+2cd+d²)= (a - b)² / (c + d)²= (.356 -.106)² / (.632 + .368)²= (.25)² = .0625
Fractions and Decimals If √4096 =64 ,then the value of √40.96 + √0.4096 + √0.004096 + √0.00004096 is ? 7.1104 .71104 71.104 711.04 7.1104 .71104 71.104 711.04 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √4096/100+ √4096/10000 + √4096/1000000 + √4096/100000000=√4096 / 10 + √4096/ 100 + √4096/ 1000 + √4096/ 10000=64/10 + 64/100 + 64/1000 + 64/10000=6.4 + .64 + .064 + .0064 = 7.1104
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