Fractions and Decimals Find the integer which when decreased by 2 is 80 times the reciprocal of the same number 11 13 12 10 11 13 12 10 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the number be X Decreasing 2 from XX - 2 = 80 x (1/X)X^2 - 2X = 80X^2 -2x -80 = 0(X-10)(X+8) = 0x=10,-8X has two values, but among the given options X value should be 10
Fractions and Decimals ( 20 + 8 x 0.5 ) / ( 20 - ? ) = 12 20 18 14 16 20 18 14 16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let (20 + 8 x 0.5) / ( 20 - y) =12Then, 24 =12 x (20 - y)∴ 12y = 216⇒ y = 18
Fractions and Decimals (.23 - .023) / ( .0023 / 23 ) = ? 2077 2770 2070 207 2077 2770 2070 207 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (.23 - .023) / ( .0023 / 23 ) = .207 / (.0023 / 23) = .207 / .0001=.2070 / .0001 = 2070
Fractions and Decimals If √5 = 2.24, then the value of 3√5 / 2√5 - 0.48 is ? 168 None of these 1.68 16.8 168 None of these 1.68 16.8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = 3√5 / 2√5 - 0.48= (3 x 2.24) / (2 x 2.24) - 0.48= 6.72 / 4.48 - 0.48 = 6.72 / 4 = 1.68
Fractions and Decimals 0.000033 / 0.11=? 0.0003 0.03 0.3 0.003 0.0003 0.03 0.3 0.003 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.000033 / 0.11= 0.0033 / 11=.0003
Fractions and Decimals The value of [(0.96)³- (0.1)³] / [(0.96)² + 0.096 + (0.1)²] is : 0.36 0.46 0.86 0.56 0.36 0.46 0.86 0.56 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression=[(0.96)³ - (0.1)³] / [(0.96)² + (0.96 x 0.1) + (0.1)²]= [(a³ - b³) / (a² + ab + b²)] = (a - b)= (0.96 - 0.1)= 0.86
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