C Programming Determine Output:void main(){ char s[]="man"; int i; for(i=0; s[i]; i++) printf("%c%c%c%c ", s[i], *(s+i), *(i+s), i[s]);} None of These mmmm nnnn aaaa Compiler Error mmm nnn aaa None of These mmmm nnnn aaaa Compiler Error mmm nnn aaa ANSWER DOWNLOAD EXAMIANS APP
C Programming Who is father of C Language? Dennis Ritchie James F. Codd Dr. Gosling Bjarne Stroustrup Dennis Ritchie James F. Codd Dr. Gosling Bjarne Stroustrup ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ int c[] = {2.8,3.4,4,6.7,5}; int j, *p=c, *q=c; for(j=0;j<5;j++){ printf(" %d ", *c); ++q; } for(j=0;j<5;j++){ printf(" %d ", *p); ++p; }} 2.8 2.8 2.8 2.8 2.8 2.8 3.4 4 2.8 3.4 4 6.7 5 2.8 3.4 4 6.7 2 2 2 2 2 2 3 4 6 5 2 3 4 6 5 2 3 4 6 5 2.8 2.8 2.8 2.8 2.8 2.8 3.4 4 2.8 3.4 4 6.7 5 2.8 3.4 4 6.7 2 2 2 2 2 2 3 4 6 5 2 3 4 6 5 2 3 4 6 5 ANSWER DOWNLOAD EXAMIANS APP
C Programming What is the output of the following statements?int b=15, c=5, d=8, e=8, a;a = b>c ? c>d ? 12 : d>e ? 13 : 14 : 15;printf("%d", a); 15 Garbage Value 14 12 13 15 Garbage Value 14 12 13 ANSWER DOWNLOAD EXAMIANS APP
C Programming String concatenation means - Partitioning the string into two strings. Comparing the two strings to define the larger one. Combining two strings. Merging two strings. Extracting a substring out of a string. Partitioning the string into two strings. Comparing the two strings to define the larger one. Combining two strings. Merging two strings. Extracting a substring out of a string. ANSWER DOWNLOAD EXAMIANS APP
C Programming Size of the array need not be specified, when It is a formal parameter It is a declaratrion All of these Initialization is a part of definition It is a formal parameter It is a declaratrion All of these Initialization is a part of definition ANSWER DOWNLOAD EXAMIANS APP
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