C Programming Determine Output:void main(){ char s[]="man"; int i; for(i=0; s[i]; i++) printf("%c%c%c%c ", s[i], *(s+i), *(i+s), i[s]);} mmm nnn aaa mmmm nnnn aaaa None of These Compiler Error mmm nnn aaa mmmm nnnn aaaa None of These Compiler Error ANSWER DOWNLOAD EXAMIANS APP
C Programming Comment on the following?const int *ptr; Both of the above We can change the pointer as well as the value pointed by it. We cannot change the pointer ptr itself. We cannot change the value pointed by ptr. Both of the above We can change the pointer as well as the value pointed by it. We cannot change the pointer ptr itself. We cannot change the value pointed by ptr. ANSWER DOWNLOAD EXAMIANS APP
C Programming #includevoid main(){ int *ptr, a=10; ptr = &a; *ptr += 1; printf("%d, %d", *ptr, a);} 10, 10 10, 11 11, 10 11, 11 10, 10 10, 11 11, 10 11, 11 ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the final value of the digit?void main(){ int digit = 0; for( ; digit <= 9; ) digit++; digit *= 2; --digit;} 16 -1 20 17 19 16 -1 20 17 19 ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of the program if the array begins at address 65486?#includevoid main(){ int arr[] = {12, 14, 15, 23, 45}; printf("%u, %u", arr, &arr);} 65486, 65488 65486, 65487 None of these 65486, 65490 65486, 65486 65486, 65488 65486, 65487 None of these 65486, 65490 65486, 65486 ANSWER DOWNLOAD EXAMIANS APP
C Programming What is the output of given program if user enter "xyz" ?#includevoid main(){float age, AgeInSeconds;int value;printf("Enter your age:");value=scanf("%f", &age);if(value==0){printf("\\nYour age is not valid");}AgeInSeconds = 365 * 24 * 60 * 60 * age;printf("\\n You have lived for %f seconds", AgeInSeconds);} Complier error Enter your age: xyz Your age is not valid Enter your age: xyz You have lived for 0 seconds Enter your age : xyz Your age is not valid Complier error Enter your age: xyz Your age is not valid Enter your age: xyz You have lived for 0 seconds Enter your age : xyz Your age is not valid ANSWER DOWNLOAD EXAMIANS APP
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