Data Types and Variables Determine output:public class Test{ int a = 10; public void method(int a){ a += 1; System.out.println(++a); } public static void main(String args[]){ Test t = new Test(); t.method(3); }} 12 11 None of these 4 5 12 11 None of these 4 5 ANSWER DOWNLOAD EXAMIANS APP
Data Types and Variables Automatic type conversion in Java takes place when Two type are compatible and size of destination type is shorter than source type. Two type are compatible and size of destination type is equal of source type. Two type are compatible and size of destination type is larger than source type. All of these Two type are compatible and size of destination type is shorter than source type. Two type are compatible and size of destination type is equal of source type. Two type are compatible and size of destination type is larger than source type. All of these ANSWER DOWNLOAD EXAMIANS APP
Data Types and Variables What will be the output for the below code ?1. public class Test{2. public static void main(String[] args){3. byte i = 128;4. System.out.println(i);5. }6. } Compilation fails with an error at line 4 Compilation fails with an error at line 3 0 128 None of these Compilation fails with an error at line 4 Compilation fails with an error at line 3 0 128 None of these ANSWER DOWNLOAD EXAMIANS APP
Data Types and Variables What is the output for the below code?public class Test{ int _$; int $7; int do; public static void main(String argv[]){ Test test = new Test(); test.$7=7; test.do=9; System.out.println(test.$7); System.out.println(test.do); System.out.println(test._$); }} Compile error - do is not valid identifier. None of these 7 9 0 7 0 0 Compile error - $7 is not valid identifier. Compile error - do is not valid identifier. None of these 7 9 0 7 0 0 Compile error - $7 is not valid identifier. ANSWER DOWNLOAD EXAMIANS APP
Data Types and Variables What is the output for the below code ?class A{ int k; boolean istrue; static int p; public void printValue(){ System.out.print(k); System.out.print(istrue); System.out.print(p); }}public class Test{ public static void main(String argv[]){ A a = new A(); a.printValue(); }} Compile error - static variable must be initialized before use. None of these 0 false 0 0 0 0 0 true 0 Compile error - static variable must be initialized before use. None of these 0 false 0 0 0 0 0 true 0 ANSWER DOWNLOAD EXAMIANS APP
Data Types and Variables What is the output for the below code ?1. public class Test{2. public static void main(String[] args){3. int i = 010;4. int j = 07;5. System.out.println(i);6. System.out.println(j);7. }8. } Compilation fails with an error at line 3 None of these 8 7 10 7 Compilation fails with an error at line 5 Compilation fails with an error at line 3 None of these 8 7 10 7 Compilation fails with an error at line 5 ANSWER DOWNLOAD EXAMIANS APP
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