Engineering Economics Current ratio is: (Current assets + loans advances)/Current liabilities None of these (Current assets + loans)/Current liabilities Current assets/Current liabilities (Current assets + loans advances)/Current liabilities None of these (Current assets + loans)/Current liabilities Current assets/Current liabilities ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics In a cash-flow diagram: A vertical arrow pointing up indicates a positive cash flow Time 0 is considered to be the present Time 1 is considered to be the end of time period 1 All of these A vertical arrow pointing up indicates a positive cash flow Time 0 is considered to be the present Time 1 is considered to be the end of time period 1 All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics A man loans P 187,400 from a bank with interest at 5% compounded annually. He agrees to pay his obligations by paying 8 equal annual payments, the first being due at the end of 10 years. Find the annual payments. P 43,489.47 P 43,600.10 P 43,763.20 P 43,263.91 P 43,489.47 P 43,600.10 P 43,763.20 P 43,263.91 ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics A type of bond to which are attached coupons indicating the interest due and the date when such interest is to be paid is called ______. Collateral trust bond Coupon bond Registered bond Mortgage bond Collateral trust bond Coupon bond Registered bond Mortgage bond ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics The institute of Electronics and Communications Engineers of the Philippines (IECEP) is planning to put up its own building. Two proposals being considered are:A. The construction of the building now to cost P 400,000B. The construction of a smaller building now to cost P300,000 and at the end of 5 years, an extension to be added to cost P 200,000.By how much is proposal B more economical than proposal A if interest rate is 20% and depreciation to be neglected? P 19,122.15 P 19,518.03 P 19,423.69 P 19,624.49 P 19,122.15 P 19,518.03 P 19,423.69 P 19,624.49 ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics The interest calculated on the basis of 365 days a year, is known as: None of these Interest Exact simple interest Ordinary simple interest None of these Interest Exact simple interest Ordinary simple interest ANSWER DOWNLOAD EXAMIANS APP
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