Chemical Engineering Thermodynamics Co-efficient of performance for a reversed Carnot cycle working between temperatures T₁ and T₂ (T₁ > T₂) is T₂/(T₁ - T₂) (T₁ - T₂)/T₂ (T₁ - T₂)/T₁ T₁/(T₁ - T₂) T₂/(T₁ - T₂) (T₁ - T₂)/T₂ (T₁ - T₂)/T₁ T₁/(T₁ - T₂) ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics A Carnot cycle consists of the following steps : Two isothermals and two isentropics Two isothermals and two isochorics Two isochorics and two isobarics Two isobarics and two isothermals Two isothermals and two isentropics Two isothermals and two isochorics Two isochorics and two isobarics Two isobarics and two isothermals ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Entropy of a substance remains constant during a/an __________ change. Reversible isothermal None of these Reversible adiabatic Irreversible isothermal Reversible isothermal None of these Reversible adiabatic Irreversible isothermal ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Joule-Thomson co-efficient for a perfect gas is None of these Positive Negative Zero None of these Positive Negative Zero ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics In the ammonia synthesis reaction, N₂ + 3H₂ ⇋ 2NH₃ + 22.4 kcal, the formation of NH₃ will be favoured by Low temperature only Low pressure High temperature Both low temperature and high pressure Low temperature only Low pressure High temperature Both low temperature and high pressure ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics In an ideal solution, the activity of a component equals its Fugacity at the same temperature and pressure Partial pressure None of these Mole fraction Fugacity at the same temperature and pressure Partial pressure None of these Mole fraction ANSWER DOWNLOAD EXAMIANS APP
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