Stoichiometry Assume that benzene is insoluble in water. The normal boiling points of benzene and water are 80.1 and 100°C respectively. At a pressure of 1 atm, the boiling point of a mixture of benzene and water is 80.1°C Greater than 80.1°C but less than 100°C Less than 80.1°C 100°C 80.1°C Greater than 80.1°C but less than 100°C Less than 80.1°C 100°C ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry For the gaseous phase reaction, N₂ + O₂ ⇋ 2NO, ΔH = + 80 kJ/kg. mole; the decomposition of NO is favoured by Increasing the concentration of N₂ Decrease in pressure Decrease in temperature Increase in pressure Increasing the concentration of N₂ Decrease in pressure Decrease in temperature Increase in pressure ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH₄ + 2O₂ → CO₂ + 2H₂O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. If the average specific heat of all the gases/vapour is 40 J/mole.K, the maximum temperature rise of the exhaust gases in °C would be approximately equal to 1735 1225 1525 1335 1735 1225 1525 1335 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Internal energy of a substance comprises of the __________ energy. Rotational Vibrational Translational All of these Rotational Vibrational Translational All of these ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry In a binary liquid solution of components A and B, if component A exhibits positive deviation from Raoult's law, then component B May exhibit either positive or negative deviation from Raoult's law Exhibits negative deviation from Raoult's law Obeys Raoult's law Exhibits positive deviation from Raoult's law May exhibit either positive or negative deviation from Raoult's law Exhibits negative deviation from Raoult's law Obeys Raoult's law Exhibits positive deviation from Raoult's law ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Which of the following holds good for a solution obeying Raoult's law (i.e., an ideal solution) (where, ΔH = heat of mixing, and ΔV = volume change on mixing ) ? ΔV = 0 Both B and C ΔH = 0 ΔH = 1 (+ ve)and Δ V = -ve ΔV = 0 Both B and C ΔH = 0 ΔH = 1 (+ ve)and Δ V = -ve ANSWER DOWNLOAD EXAMIANS APP
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